我Camera.setTranslate(x, 0, z)在drawChild中使用过,其中x位置用于旋转虚拟化,z用于重叠.然后出现重叠问题,因为最后一个项目位于顶层,第一个位于底层.因此,在onCreate()调用this.setChildrenDrawingOrderEnabled(true)和覆盖的方法中protected int getChildDrawingOrder (int childCount, int i) {},我可以更改中间行和后续行的顺序.这个想法被雷纳,谁建议我在其他我的帖子几乎大约同样的事情给出这里.
我的getChildDrawingOrder(int,int)实现让我需要重叠:
@Override
protected int getChildDrawingOrder (int childCount, int i) {
int centerChild = 0;
//find center row
if ((childCount % 2) == 0) { //even childCount number
centerChild = childCount / 2; // if childCount 8 (actualy 0 - 7), then 4 and 4-1 = 3 is in centre.
int otherCenterChild = centerChild - 1;
//Which more in center?
View child = this.getChildAt(centerChild);
final int top = child.getTop();
final int bottom = child.getBottom();
//if this row goes through center then this
final int absParentCenterY = getTop() + getHeight() / 2;
//Log.i("even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild);
if ((top < absParentCenterY) && (bottom > absParentCenterY)) {
//this child is in center line, so it is last
//centerChild is in center, no need to change
} else {
centerChild = otherCenterChild;
}
}
else {//not even - done
centerChild = childCount / 2;
//Log.i("not even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild);
}
int rez = i;
//find drawIndex by centerChild
if (i > centerChild) {
//below center
rez = (childCount - 1) - i + centerChild;
} else if (i == centerChild) {
//center row
//draw it last
rez = childCount - 1;
} else {
//above center - draw as always
// i < centerChild
rez = i;
}
//Log.i("return", "" + rez);
return rez;
}
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我希望这篇文章将来会对某人有所帮助
屏幕截图实际上与我在问题中提到的几乎相同.我使用了alpha,所以重叠的项目有点透明:

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