Django - ModelForm创建还是更新?

Pie*_*NAY 11 django django-models django-forms django-views

我需要一个允许在计划中创建或添加会话的表单

模型

class Session(models.Model):
    tutor = models.ForeignKey(User)
    start_time = models.DateTimeField()
    end_time = models.DateTimeField()
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形成

class SessionForm(forms.ModelForm):
    class Meta:
        model = Session
        exclude = ['tutor']
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查看以呈现表单

def editor(request):
    if request.method == 'GET':
        if request.GET['id'] != '0':
            # The user has selected a session
            session = Session.objects.get(id=request.GET['id'])
            form = SessionForm(instance=session)
        else:
            # The user wants to add a new session
            form = SessionForm()
        return render_to_response('planner/editor.html',
            {'form': form,}, context_instance=RequestContext(request),)
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模板editor.html

<form action="/planner/post" method="post">{% csrf_token %}
{{ form.as_p }}
</form>
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查看以发布值

def post(request):
    if request.method == 'POST':
        form = SessionForm(request.POST)
        if form.is_valid():
            form.instance.tutor = request.user
            form.save()
            obj = {'posted': True}
            return HttpResponse(json.dumps(obj), mimetype='application/json')
        else:
            return render_to_response('planner/editor.html',
                form, context_instance=RequestContext(request),)
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问题

始终创建会话(从不更新)

问题

  • 在我看来post,我怎么知道会话必须更新而不是创建?
  • 有没有办法简化这段代码?

Ala*_*air 18

如果要更新会话,则需要在绑定表单时提供实例.

如果表单是有效的,你就可以节省commit=False,并更新导师.

form = SessionForm(instance=instance, data=request.POST)
if form.is_valid():
    instance = form.save(commit=False)
    instance.tutor = request.user
    instance.save()
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  • 这是个主意,虽然这是[反向你的网址]的好习惯(https://docs.djangoproject.com/en/dev/topics/http/urls/#naming-url-patterns),然后你可以有`action = "{%url edit_session session.pk%}"`` (2认同)