Arduino串行中断

Question

我正在研究Arduino Mega 2560项目.在Windows 7 PC上,我使用的是Arduino1.0 IDE.我需要建立一个波特率为115200的串行蓝牙通信.当RX上的数据可用时,我需要接收一个中断.我见过的每一段代码都使用"轮询",这是在Arduino循环中放置Serial.available的条件.如何在Arduino的循环中替换这种方法以获得中断及其服务程序？似乎attachInterrupt()没有提供此目的.我依靠中断从睡眠模式中唤醒Arduino.

我开发了这个简单的代码,它应该打开连接到引脚13的LED.

    #include <avr/interrupt.h> 
    #include <avr/io.h> 
    void setup()
    {
       pinMode(13, OUTPUT);     //Set pin 13 as output

       UBRR0H = 0;//(BAUD_PRESCALE >> 8); // Load upper 8-bits of the baud rate value into the high byte of the UBRR register 
       UBRR0L = 8; // Load lower 8-bits of the baud rate value into the low byte of the UBRR register 
       UCSR0C |= (1 << UCSZ00) | (1 << UCSZ10); // Use 8-bit character sizes 
       UCSR0B |= (1 << RXEN0) | (1 << TXEN0) | (1 << RXCIE0);   // Turn on the transmission, reception, and Receive interrupt      
    }

    void loop()
    {
      //Do nothing
    }

    ISR(USART0_RXC_vect)
    {    
      digitalWrite(13, HIGH);   // Turn the LED on          
    }

问题是从不提供子程序.

Answer 1

最后我发现了我的问题.我改变了中断向量"USART0_RXC_vect" USART0_RX_vect.我还添加interrupts();了启用全局中断,它运行良好.

代码是:

#include <avr/interrupt.h> 
#include <avr/io.h> 
void setup()
{
   pinMode(13, OUTPUT); 

   UBRR0H = 0; // Load upper 8-bits of the baud rate value into the high byte of the UBRR register 
   UBRR0L = 8; // Load lower 8-bits of the baud rate value into the low byte of the UBRR register 
   UCSR0C |= (1 << UCSZ00) | (1 << UCSZ10); // Use 8-bit character sizes 
   UCSR0B |= (1 << RXEN0) | (1 << TXEN0) | (1 << RXCIE0);   // Turn on the transmission, reception, and Receive interrupt      
   interrupts();
}

void loop()
{

}

ISR(USART0_RX_vect)
{  
  digitalWrite(13, HIGH);   // set the LED on
  delay(1000);              // wait for a second
}

谢谢你的回复!!!!