Caf*_*eek 5 sql sql-server join
我想把两张桌子连在一起,但有一个奇怪的要求.
通常情况下,我会加入该客户的记录和代码匹配的位置
SELECT *
FROM DataTable d
JOIN LookupTable l
ON d.LookupCode = l.LookupCode
AND d.Customer = l.Customer
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但是,我需要做的是从查找表中连接三行.匹配的ID,以及基于另一列(Order)中的排序顺序的前后行(如果存在).然后,我需要对结果进行排序,首先匹配的记录,然后是之前的查找记录,然后是匹配记录之后的查找记录.
有关实现这一目标的最佳方法的任何想法?
例:
Lookup:
Customer Code Order
12345 A 1
12345 B 2
12345 C 3
12345 D 4
12345 E 5
22222 A 1
22222 B 2
22222 D 4
22222 E 5
Data:
Customer Code
12345 B
12345 D
22222 B
22222 D
Result I need
Customer Code
12345 B
12345 A
12345 C
12345 D
12345 C
12345 E
22222 B
22222 A
22222 D
22222 D
22222 B
22222 E
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不是最有效或最优雅的,但它确实有效!
数据设置:
CREATE TABLE LookupTable (Customer int, Code nvarchar(1), OrderCol int)
CREATE TABLE DataTable (Customer int, Code nvarchar(1))
insert LookupTable values (12345,'A',1),(12345,'B',2),(12345,'C',3),(12345,'D',4),(12345,'E',5),(22222,'A',1),(22222,'B',2),(22222,'D',4),(22222,'E',5)
insert DataTable values (12345,'B'),(12345,'D'),(22222,'B'),(22222,'D')
select * from LookupTable
select * from DataTable
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查询:
;with LookupCte as (
SELECT *
, ROW_NUMBER() OVER (PARTITION BY Customer ORDER BY OrderCol ASC) AS LookUpOrder
FROM LookupTable
)
, DataCTE as (
SELECT dt.Customer
, dt.Code
, lu.LookUpOrder
, (lu.LookUpOrder - 1) AS OrderColNVe
, (lu.LookUpOrder + 1) AS OrderColPVe
, ROW_NUMBER() OVER (PARTITION BY dt.Customer ORDER BY dt.Code ASC) AS DataCteRowNumber
FROM DataTable dt
INNER JOIN LookupCte lu
ON lu.Customer = dt.Customer
AND lu.Code = dt.Code
)
, UnionCTE As (
SELECT d.Customer
, d.Code
, d.DataCteRowNumber
, 1 AS [CustomOrder]
FROM DataCTE d
UNION ALL
SELECT lt.Customer
, lt.Code
, d.DataCteRowNumber
, 2 AS [CustomOrder]
FROM DataCTE d
INNER JOIN LookupCte lt on lt.Customer = d.Customer
AND lt.LookUpOrder = d.OrderColNVe
UNION ALL
SELECT lt.Customer
, lt.Code
, d.DataCteRowNumber
, 3 AS [CustomOrder]
FROM DataCTE d
INNER JOIN LookupCte lt on lt.Customer = d.Customer
AND lt.LookUpOrder = d.OrderColPVe
)
SELECT u.Customer
, u.Code
FROM UnionCTE u
ORDER BY u.Customer, u.DataCteRowNumber, u.CustomOrder
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给出:
Customer Code
----------- ----
12345 B
12345 A
12345 C
12345 D
12345 C
12345 E
22222 B
22222 A
22222 D
22222 D
22222 B
22222 E
(12 row(s) affected)
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