假设这个结构的数据:
test <- structure(list(characteristic = structure(c(1L, 2L, 3L, 1L, 2L
), .Label = c("Factor1", "Factor2", "Factor3"), class = "factor"), 
    es = c(1.2, 1.4, 1.6, 1.3, 1.5), ci_low = c(1.1, 1.3, 1.5, 
    1.2, 1.4), ci_upp = c(1.3, 1.5, 1.7, 1.4, 1.6), label = structure(c(1L, 
    3L, 5L, 2L, 4L), .Label = c("1.2 (1.1, 1.3)", "1.3 (1.2, 1.4)", 
    "1.4 (1.3, 1.5)", "1.5 (1.4, 1.6)", "1.6 (1.5, 1.7)"), class = "factor"), 
    set = structure(c(1L, 1L, 1L, 2L, 2L), .Label = c("H", "S"
    ), class = "factor")), .Names = c("characteristic", "es", 
"ci_low", "ci_upp", "label", "set"), class = "data.frame", row.names = c(NA, 
-5L))
并运行代码:
p <- ggplot(test, aes(x=characteristic, y=es, ymin=ci_low, ymax=ci_upp)) + geom_pointrange() +
  coord_flip() + geom_hline(aes(x=0), lty=2) + 
  facet_wrap(~ set, ncol = 1) +
  theme_bw() + 
  opts(strip.text.x = theme_text())
产生这样的输出:

到目前为止都很好.但是,我想从我的下方面板中删除空的Factor3级别,但无法找到方法.有没有办法做到这一点?
感谢帮助.
San*_*att 23
编辑更新为ggplot2 0.9.3
这是另一种解决方案.它使用facet_grid和space = "free"; 它也使用geom_point()和geom_errorbarh(),因此没有必要coord.flip().此外,x轴刻度线标签仅出现在下面板上.在下面的代码中,theme命令不是必需的 - 它用于旋转条带文本以水平显示.使用test上面的数据框,以下代码应该产生你想要的:
library(ggplot2)
p <- ggplot(test, aes(y = characteristic, x = es, xmin = ci_low, xmax = ci_upp)) +
   geom_point() +
   geom_errorbarh(height = 0) +
   facet_grid(set ~ ., scales = "free", space = "free") +
   theme_bw() +
   theme(strip.text.y = element_text(angle = 0))
p
该解决方案基于Wickham的ggplot2书中第124页的示例.
Tyl*_*ker 14
用途scales = "free"如下:
p <- ggplot(test, aes(x=characteristic, y=es, ymin=ci_low, ymax=ci_upp)) + geom_pointrange() +
  coord_flip() + geom_hline(aes(x=0), lty=2) + 
  facet_wrap(~ set, ncol = 1, scales="free") +
  theme_bw() + 
  opts(strip.text.x = theme_text())
p
哪个产生:

编辑:我实际上认为我更喜欢drop = TRUE这个解决方案的论点,如:
p <- ggplot(test, aes(x=characteristic, y=es, ymin=ci_low, ymax=ci_upp)) + 
  geom_pointrange() +
  coord_flip() + geom_hline(aes(x=0), lty=2) + 
  facet_wrap(~ set, ncol = 1,  drop=TRUE) +
  theme_bw() + 
  opts(strip.text.x = theme_text())
p