DB2 SQL SUM和分组

Question

我在查询和分组时遇到问题。

我需要以下输出：

officr, cbal, sname  
ABC, 500.00, TOM JONES  
ABC, 200.00, SUE JONES  
ABC TOTAL 700.00  

RAR, 100.10, JOE SMITH  
RAR, 200.05,  MILES SMITH  
RAR TOTAL 300.15  

下面的SQL产生错误：

[DB2 for i5 / OS] SQL0122-列SNAME或SELECT列表中的表达式无效。

SELECT
    lnmast.officr,  SUM(LNMAST.CBAL), lnmast.sname
FROM
    LNMAST
WHERE LNMAST.RATCOD IN (6,7,8) AND STATUS NOT IN ('2','8')
group by lnmast.officr

Answer 1

GROUP BY GROUPING SETS是用于分组/计算数据的强大工具。它使您可以将非聚合数据与聚合数据合并到一个查询结果中。

SELECT lnmast.officr,  SUM(LNMAST.CBAL), lnmast.sname
FROM LNMAST
WHERE LNMAST.RATCOD IN (6,7,8) 
  AND STATUS NOT IN ('2','8')
GROUP BY GROUPING SETS ((lnmast.officr, lnmast.sname),(lnmast.officr))

IBM DOCS的示例：www.ibm.com/support/knowledgecenter/en / ... ：

  SELECT WEEK(SALES_DATE) AS WEEK,
         DAYOFWEEK(SALES_DATE) AS DAY_WEEK,
         SALES_PERSON, SUM(SALES) AS UNITS_SOLD       
  FROM SALES 
  WHERE WEEK(SALES_DATE) = 13
  GROUP BY GROUPING SETS ( (WEEK(SALES_DATE), SALES_PERSON),
                           (DAYOFWEEK(SALES_DATE), SALES_PERSON))
  ORDER BY WEEK, DAY_WEEK, SALES_PERSON

结果是：

  WEEK        DAY_WEEK    SALES_PERSON    UNITS_SOLD 
  ----------- ----------- --------------- -----------
           13           - GOUNOT                   32
           13           - LEE                      33
           13           - LUCCHESSI                 8
            -           6 GOUNOT                   11
            -           6 LEE                      12
            -           6 LUCCHESSI                 4
            -           7 GOUNOT                   21
            -           7 LEE                      21
            -           7 LUCCHESSI                 4