iOS无法获得人的形象

Rin*_*nat 4 addressbook ios

我有两个tableViewControllers.第一个有联系人列表.另一个显示详细的人的信息.

第一个tableViewController的一大块代码

ABAddressBookRef addressBook = ABAddressBookCreate();
ABRecordRef source = ABAddressBookCopyDefaultSource(addressBook);
NSArray *allPeople = (__bridge_transfer NSArray*)ABAddressBookCopyArrayOfAllPeopleInSourceWithSortOrdering(addressBook, source,kABPersonSortByFirstName);
for ( int i = 0; i < [allPeople count]; i++ )
{
    ...
    contactClass = [[ContactClass alloc] initWithName:name surName:surName manID:[allPeople objectAtIndex:i]];
    ...
}
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第二个tableViewController的代码块

ABRecordRef person = (__bridge  ABRecordRef)contactClass.manID;
BOOL isHasImage = ABPersonHasImageData(person);
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变量isHasImage始终为false,即使联系人具有头像.我甚至在第一个tableViewController上检查了这个,如果有人有头像,那么它返回true和image.

有谁知道为什么我不能得到联系人图像?

ps contactClass.manID是的类型id.它有一个正确的地址,因为ABMultiValueRef multiValue = ABRecordCopyValue((__bridge ABRecordRef)contactClass.manID, kABPersonPhoneProperty);在第二个tableViewController中返回正确的值

ale*_*mbu 10

我可能为你找到一个解决方案为时已晚,但也许这会帮助那些遇到同样问题的人.在iOS 5.x 上的副本上,副本(例如,从使用的数组中获得)看起来ABPersonHasImageData()并且ABPersonCopyImageDataWithFormat()不能按预期工作.您可以像这样解决它:ABRecordRefABContactRefABAddressBookCopyArrayOfAllPeople()

- (UIImage*)imageForContact: (ABRecordRef)contactRef {
    UIImage *img = nil;

    // can't get image from a ABRecordRef copy
    ABRecordID contactID = ABRecordGetRecordID(contactRef);
    ABAddressBookRef addressBook = ABAddressBookCreate();

    ABRecordRef origContactRef = ABAddressBookGetPersonWithRecordID(addressBook, contactID);

    if (ABPersonHasImageData(origContactRef)) {
        NSData *imgData = (NSData*)ABPersonCopyImageDataWithFormat(origContactRef, kABPersonImageFormatOriginalSize);
        img = [UIImage imageWithData: imgData]; 

        [imgData release];
    }

    CFRelease(addressBook);

    return img;
}
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