我的数学怎么了?

old*_*new 0 c floating-point int

我有一个涉及浮点数和整数的函数.当我运行代码时,结果出错了.当我为input_voltage输入4.3时,我得到小数的3803和HEX的EDB.正确的答案应该是3808和EE0.谁能告诉我可能会发生什么?

#include <stdio.h>

int digital_encoding(float voltage);

int main()
{
    float input_voltage;
    int valid, ch;

    do{
        printf("Please enter the input voltage between 0 and 5 volts: \n");
        valid = scanf("%f", &input_voltage);
        if(input_voltage <= 0){
            printf("Enter a number larger than 0! \n");
            valid = 0;
        }
        if(input_voltage >= 5){
            printf("Enter a number less than 5! \n");
            valid = 0;
        }
    }while(valid != 1);

    digital_encoding(input_voltage);
}
int digital_encoding(float voltage)
{
    int dig_encode;
    dig_encode = ((voltage + 5)*(4095/10));
    printf("The digital encoding equals %d in decimal, and %X in HEX.\n", dig_encode, dig_encode);
    return dig_encode;
}
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ami*_*mit 6

4095/10 是409而不是409.5,这是整数算术,所以它是向下舍入的.

你可能正在寻找 4095.0 / 10[或只是409.5]