在Spring 3.1中通过IP地址进行身份验证:最明智的方法吗？

Question

我使用Spring Security 3.1实现了LDAP身份验证.我的security.xml文件发布在下面.

我需要更改我的身份验证过程,以便如果用户从"白名单"(保存在数据库表中)中的IP地址进入站点,则该用户应自动使用Spring 3.1进行身份验证,然后重定向远离登录屏幕(不是我的想法,我被告知这样).

如果用户不是来自白名单IP地址之一,则应强制他/她在登录页面上进行LDAP身份验证.

我是Spring和Spring Security的新手,所以我参阅了Spring 3.1参考文档,并阅读了第一部分.在那里,我读到了一些建议,如果你有任何特殊的认证需求,你应该阅读 第二节的体系结构和实现.我做到了,非常缓慢并记笔记.

但是,由于我是所有这一切的新手,我不确定我是否完全理解我需要做什么以及最聪明的方法.

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更新3:我得到了骨架代码,这是我最终得到的文件

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我的自定义AuthenticationProvider实现,用于通过IP地址进行身份验证

// Authentication Provider To Authenticate By IP Address With Allowed IPs
// Stored in a db table


package acme.com.controller.security;

//import acme.com.controller.security.CustomUserInfoHolder;

import org.springframework.security.authentication.AuthenticationProvider;
import org.springframework.security.authentication.UsernamePasswordAuthenticationToken;
import org.springframework.security.core.Authentication;
import org.springframework.security.core.AuthenticationException;
import org.springframework.security.web.authentication.WebAuthenticationDetails;
import org.springframework.security.core.context.SecurityContextHolder;
import org.springframework.security.core.authority.mapping.GrantedAuthoritiesMapper;
import org.springframework.security.core.authority.mapping.NullAuthoritiesMapper;
import org.springframework.security.authentication.UsernamePasswordAuthenticationToken;
import org.springframework.security.core.userdetails.UserDetails;

import org.apache.log4j.Logger;


public class CustomIPAddressAuthenticationProvider implements AuthenticationProvider
{

    private static final Logger logger = Logger.getLogger(CustomIPAddressAuthenticationProvider.class);
    private GrantedAuthoritiesMapper authoritiesMapper = new NullAuthoritiesMapper();


    @Override
    public Authentication authenticate(Authentication authentication)
    throws AuthenticationException {


        WebAuthenticationDetails wad = null;
        String userIPAddress         = null;
        boolean isAuthenticatedByIP  = false;

        // Get the IP address of the user tyring to use the site
        wad = (WebAuthenticationDetails) authentication.getDetails();
        userIPAddress = wad.getRemoteAddress();


        logger.debug("userIPAddress == " + userIPAddress);

        // Compare the user's IP Address with the IP address in the database
        // stored in the USERS_AUTHENTICATED_BY_IP table & joined to the
        // USERS tabe to make sure the IP Address has a current user
        //isAuthenticatedByIP =  someDataObject.hasIPAddress(userIPAddress);
        isAuthenticatedByIP = true;


        // Authenticated, the user's IP address matches one in the database
        if (isAuthenticatedByIP)
        {

            logger.debug("isAuthenticatedByIP is true, IP Addresses match");
            UserDetails user = null;


            UsernamePasswordAuthenticationToken result = null;

            result = new UsernamePasswordAuthenticationToken("John Principal",
                                                              "PlaceholderPWE"); 

            result.setDetails(authentication.getDetails());

            return result;
        }


        // Authentication didn't happen, return null to signal that the 
        // AuthenticationManager should move on to the next Authentication provider
        return null;
    }


    @Override
    public boolean supports(Class<? extends Object> authentication)
    {
        // copied it from AbstractUserDetailsAuthenticationProvider
        return(UsernamePasswordAuthenticationToken.class.isAssignableFrom(authentication));
    }

}

我的*-security.xml文件

<beans xmlns="http://www.springframework.org/schema/beans"
  xmlns:s="http://www.springframework.org/schema/security"
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
  xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security-3.1.xsd">

    <s:http pattern="/login*" security="none"/>
    <s:http pattern="/search*" security="none"/>
    <s:http pattern="/css/**" security="none"/>
    <s:http pattern="/js/**" security="none"/>
    <s:http pattern="/images/**" security="none"/>




    <s:http auto-config="true" use-expressions="true">
        <s:intercept-url pattern="/**" access="isAuthenticated()" />

        <s:form-login login-page="/login"
          authentication-failure-url="/loginfailed" />
        <s:logout logout-success-url="/logout" />
    </s:http>



    <s:ldap-server url = "ldap://ldap-itc.smen.acme.com:636/o=acme.com"/>


    <bean id="customIPAddressAuthenticationProvider" class="com.acme.controller.security.CustomIPAddressAuthenticationProvider" />


    <s:authentication-manager>
        <!-- Proposed: Custom Authentication Provider: Try To Authenticate BY IP Address First, IF NOT, Authenticate WiTh THE LDAP Authentication Provider -->
        <s:authentication-provider ref="customIPAddressAuthenticationProvider" />
        <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People"/>
    </s:authentication-manager>


</beans>

Answer 1

您的方法似乎很合理，您认为 Spring 将尝试每个 AuthenticationProvider 直到获得成功的结果是正确的，因此在您的情况下，您将在 LDAP 提供程序之前定义基于 IP 的提供程序。

根据您的设置，您可能无法在authentication.getDetails() 调用中获得WebAuthenticationDetails 对象。如果是这种情况，您应该将 Spring 的RequestContextListener或RequestContextFilter添加到您的 web.xml 中。然后，您将能够通过使用 RequestContextHolder 类并调用 RequestContextHolder.getRequestAttributes() 来获取源 IP 地址。

您应该只需要实现 AuthenticationProvider，不需要实现 UserDetailsS​​ervice、UserDetails 或 Authentication 类。如果您无法通过用户的 IP 地址对用户进行身份验证，则应返回 null。在这种情况下，Spring 将尝试 LDAP 提供程序。如果由于某种原因您不想将尝试传递到 LDAP，您应该抛出 AuthenticationException，这将停止该过程并最终导致用户出现 403 错误。

我希望这有帮助 ：）