Oracle SQL合并语句只有1个表和一堆值

oll*_*llo 5 sql oracle spring merge-statement

我正在使用Spring JDBC和oracle SQL.

使用SpringJDBC类MapSqlParameterSource,我已经映射了我想要合并的数据.

现在我想使用merge语句来更新/插入数据库表.我只有一个表和一堆我想要合并到它的参数.

 merge into proj.person_registry pr
using ( ! parameters should go here somehow? )
on (pr.id = :id or pr.code = :code)
when matched then 
update set pr.code             = :code,
        pr.name                 = :name,
        pr.firstname            = :firstname,
        pr.cl_gender            = :cl_gender,
        pr.cl_status            = :cl_status,
        pr.aadress              = :aadress,
        pr.aadress_date         = :aadress_date 
when not matched then
insert values (:code, :name, :firstname, :cl_gender, :cl_status, ;aadress, :aadress_date);
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我是否必须以某种方式为using 关键字创建临时表,还是有另一种方式?我怎么会这样合并呢?

pr.id和pr.code也有两个唯一的键.有时参数:idnull,当发生这种情况时,我想根据pr.code匹配到:code来到达update语句.如果我的更新包含该行,它仍然可以工作:

update set pr.code             = :code,
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a_h*_*ame 5

这应该工作:

merge into proj.person_registry pr
using ( 
  select 42 as id
         'xyz' as code,
         'Dent' as name,
         'Arthur' as firstname,
         'male' as cl_gender
         'closed' as cl_status,
         'Somewher' as aaddress,
         current_date as aaddress_date
   from dual
) t on (pr.id = t.id or pr.code = t.code)
when matched then 
update set pr.code             = t.code,
        pr.name                 = t.name,
        pr.firstname            = t.firstname,
        pr.cl_gender            = t.cl_gender,
        pr.cl_status            = t.cl_status,
        pr.aadress              = t.aadress,
        pr.aadress_date         = t.aadress_date 
when not matched then
insert values (t.code, t.name, t.firstname, t.cl_gender, t.cl_status, ;aadress, t.aadress_date);
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我不熟悉Spring的JDBC模板,但是select ... from dual通过参数占位符替换查询中的实际值应该可行.