使用C#在Active Directory中获取用户的父OU

Question

我想检查一个用户是否在特定的父OU中.

我怎样才能做到这一点？

检查下面的代码,明确说明我在寻找什么.

using System.DirectoryServices.AccountManagement;

public bool IsUserInOU(string samAccountName, string OUName){

    using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {                    
                //Check if the user is in the OU specified in OUName
                //Something like:
                //return user.IsInOU(OUName);
            }
         }
}

public void TestIt_1(){
  //The parent OU of this user is "AwesomeOU"
  string samAccountName = "Joe";
  string OUName = "AwesomeOU";
  bool expected = true;
  bool actual = IsUserInOU(samAccountName, OUName);
  Assert.AreEqual(expected, actual);
}

public void TestIt_2(){
  //The parent OU of this user is "WhateverOU"
  string samAccountName = "Mike";
  string OUName = "AwesomeOU";
  bool expected = false;
  bool actual = IsUserInOU(samAccountName, OUName);
  Assert.AreEqual(expected, actual);
}

域名:

• 国家OU
  • 很棒的OU
    • 乔
  • 无论什么OU
    • 麦克风

在empi回答后的解决方案1

使用empi提供的信息,我编写了以下方法来提取DistinguishedName中的第一个OU.完成后,其余的都是轻而易举的.

public static string GetOUForUser(string samAccountName)
    {
        using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {
                //System.Console.WriteLine(user.DistinguishedName);
                int startIndex = user.DistinguishedName.IndexOf("OU=", 1) + 3; //+3 for  length of "OU="
                int endIndex = user.DistinguishedName.IndexOf(",", startIndex);
                var group = user.DistinguishedName.Substring((startIndex), (endIndex - startIndex));
                return group;
            }
        }
    }

解决方案2在JPBlanc回答之后

public static string GetOUForUser(string samAccountName)
    {
        using (var context = new PrincipalContext(ContextType.Domain))
        {
            using (var user = UserPrincipal.FindByIdentity(context, IdentityType.SamAccountName, samAccountName))
            {
                using (DirectoryEntry deUser = user.GetUnderlyingObject() as DirectoryEntry)
                {
                    using (DirectoryEntry deUserContainer = deUser.Parent)
                    {
                        return deUserContainer.Properties["Name"].Value.ToString();
                    }
                }
            }
        }
    }

Answer 1

好的@Empi解决方案正在运行,但是UserPrincipal建立在DirectoryEntry提供parent或container只为您提供所需对象的属性的对象上,而不使用字符串方式.

/* Retreiving a principal context
 */
PrincipalContext domainContext = new PrincipalContext(ContextType.Domain, "WM2008R2ENT:389", "dc=dom,dc=fr", "dom\\jpb", "MyPwd");

/* Retreive a user
 */
UserPrincipal user = UserPrincipal.FindByIdentity(domainContext, "user1");

/* Retreive the container
 */
DirectoryEntry deUser = user.GetUnderlyingObject() as DirectoryEntry;
DirectoryEntry deUserContainer = deUser.Parent;
Console.WriteLine (deUserContainer.Properties["distinguishedName"].Value);