仅从联系人列表Android获取电子邮件地址

Question

我想只显示其电子邮件地址存在的联系人姓名.否则,联系人姓名不应显示在列表中.我怎样才能做到这一点？有人可以帮帮我吗？

Answer 1

这是我的超快速查询来提取电子邮件地址.如其他答案所示,它比拉动所有接触柱要快得多......

public ArrayList<String> getNameEmailDetails() {
    ArrayList<String> emlRecs = new ArrayList<String>();
    HashSet<String> emlRecsHS = new HashSet<String>();
    Context context = getActivity();
    ContentResolver cr = context.getContentResolver();
    String[] PROJECTION = new String[] { ContactsContract.RawContacts._ID, 
            ContactsContract.Contacts.DISPLAY_NAME,
            ContactsContract.Contacts.PHOTO_ID,
            ContactsContract.CommonDataKinds.Email.DATA, 
            ContactsContract.CommonDataKinds.Photo.CONTACT_ID };
    String order = "CASE WHEN " 
            + ContactsContract.Contacts.DISPLAY_NAME 
            + " NOT LIKE '%@%' THEN 1 ELSE 2 END, " 
            + ContactsContract.Contacts.DISPLAY_NAME 
            + ", " 
            + ContactsContract.CommonDataKinds.Email.DATA
            + " COLLATE NOCASE";
    String filter = ContactsContract.CommonDataKinds.Email.DATA + " NOT LIKE ''";
    Cursor cur = cr.query(ContactsContract.CommonDataKinds.Email.CONTENT_URI, PROJECTION, filter, null, order);
    if (cur.moveToFirst()) {
        do {
            // names comes in hand sometimes
            String name = cur.getString(1);
            String emlAddr = cur.getString(3);

            // keep unique only
            if (emlRecsHS.add(emlAddr.toLowerCase())) {
                emlRecs.add(emlAddr);
            }
        } while (cur.moveToNext());
    }

    cur.close();
    return emlRecs;
}

我尝试了'Agarwal Shankar'提供的代码,但是在我的测试设备上花了大约4秒钟来获取联系人,这段代码花了大约0.04秒.

Answer 2

public ArrayList<String> getNameEmailDetails(){
        ArrayList<String> names = new ArrayList<String>();
        ContentResolver cr = getContentResolver();
        Cursor cur = cr.query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null);
        if (cur.getCount() > 0) {
            while (cur.moveToNext()) {
                String id = cur.getString(cur.getColumnIndex(ContactsContract.Contacts._ID));
                Cursor cur1 = cr.query( 
                        ContactsContract.CommonDataKinds.Email.CONTENT_URI, null,
                        ContactsContract.CommonDataKinds.Email.CONTACT_ID + " = ?", 
                                new String[]{id}, null); 
                while (cur1.moveToNext()) { 
                    //to get the contact names
                    String name=cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME));
                    Log.e("Name :", name);
                    String email = cur1.getString(cur1.getColumnIndex(ContactsContract.CommonDataKinds.Email.DATA));
                    Log.e("Email", email);
                    if(email!=null){
                        names.add(name);
                    }
                } 
                cur1.close();
            }
        }
        return names;
    }

上面的方法返回一个具有电子邮件ID的名称的arraylist.