Java:访问指针

Question

我得到:'
需要意外类型:变量
找到:值'在标记的行(*)

for (int i = 0; i < boardSize; i++) {
    for (int j = 0; j < boardSize; j++) {
        rows[i].getSquare(j) = matrix[i][j]; // * points to the ( in (j)
        columns[j].getSquare(i) = matrix[i][j]; // * points to the ( in
        int[] b = getBox(i, j);
        int[] boxCord = getBoxCoordinates(i + 1, j + 1);
        boxes[b[0]][b[1]].getSquare(boxCord[0], boxCord[1]);
    }
}

这是我的Row类:

private Square[] row;

Row(int rowCount) {
    this.row = new Square[rowCount];
}

public Square getSquare(int index) {
    return this.row[index];
}  

请指出我在这里做错了什么,帮助我.
提前致谢.

Answer 1

您不能将某些内容分配给方法的返回值.相反,您需要向该类添加一个setSquare()方法Row:

public Square setSquare(int index, Square value) {
    this.row[index] = value;
}  

并像这样使用它:

rows[i].setSquare(j, matrix[i][j]);