Yen*_*eny 2 android handler progressdialog delayed-execution
这是关于加载的问题.我的应用程序应该等待3秒然后绘制路径.现在,加载消息框在3秒内出现,但应用程序不会等待3秒并立即绘制.我的编码有问题吗?
非常感谢!!
public void drawpath(){
// first to do some checking
if (sourceLat.equals("22.3366467") && destinationLat.equals("35.68449"))
ShowMsgDialog("Please enter the starting point and destination");
else if (sourceLat.equals("22.3366467") )
ShowMsgDialog("Please enter the starting point by touch");
else if (destinationLat.equals("35.68449") )
ShowMsgDialog("Please enter the destination by touch");
else if (pairs != null ){
// go to loading function
loading();
// Start to draw the path
String[] lngLat = pairs[0].split(",");
GeoPoint startGP = new GeoPoint((int) (Double.parseDouble(lngLat[1]) * 1E6), (int) (Double.parseDouble(lngLat[0]) * 1E6));
mc = mapView.getController();
geoPoint = startGP;
mc.setCenter(geoPoint);
mc.setZoom(15);
mapView.getOverlays().add(new DirectionPathOverlay(startGP, startGP));
......
}
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在loading()函数中:
private void loading() {
progressDialog = ProgressDialog.show(this, "Showing Data..", "please wait", true, false);
new Thread()
{
public void run()
{
try{
sleep(3000);
}
catch (Exception e){
e.printStackTrace();
}
finally{
progressDialog.dismiss();
}
}
}.start();
}
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小智 25
您也可以通过以下方式执行此操作:
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
drawPath();
}
}, 5000);
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这不会显示任何lint警告.
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