在XSLT中替换XML值

Question

我无法编辑XML,我只想在XSLT文件中更改XML数据.

<xsl:value-of select="Name" disable-output-escaping="yes"/>

XML数据的价值是"Northfield Bancorp Inc.(MHC)",我想用"Northfield Bancorp Inc."(删除"MHC")替换它.

XSLT中是否有可用的功能可以搜索并替换它？

Answer 1

如果它只是您要删除的字符串末尾的"(MHC)",则会执行以下操作:

<xsl:value-of select="
  substring-before(
    concat(Name, '(MHC)'), 
    '(MHC)'
  )
" />

如果要动态替换,可以编写如下函数:

<xsl:template name="string-replace">
  <xsl:param name="subject"     select="''" />
  <xsl:param name="search"      select="''" />
  <xsl:param name="replacement" select="''" />
  <xsl:param name="global"      select="false()" />

  <xsl:choose>
    <xsl:when test="contains($subject, $search)">
      <xsl:value-of select="substring-before($subject, $search)" />
      <xsl:value-of select="$replacement" />
      <xsl:variable name="rest" select="substring-after($subject, $search)" />
      <xsl:choose>
        <xsl:when test="$global">
          <xsl:call-template name="string-replace">
            <xsl:with-param name="subject"     select="$rest" />
            <xsl:with-param name="search"      select="$search" />
            <xsl:with-param name="replacement" select="$replacement" />
            <xsl:with-param name="global"      select="$global" />
          </xsl:call-template>
        </xsl:when>
        <xsl:otherwise>
          <xsl:value-of select="$rest" />
        </xsl:otherwise>
      </xsl:choose>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="$subject" />
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

哪个可以调用为:

<xsl:call-template name="string-replace">
  <xsl:with-param name="subject"     select="Name" />
  <xsl:with-param name="search"      select="'(MHC)'" />
  <xsl:with-param name="replacement" select="''" />
  <xsl:with-param name="global"      select="true()" />
</xsl:call-template>