如何从X获取接下来的七天并在JS中进行格式化

Question

我想打印这样的东西(一个7天的日历),但能够从我想要的任何日期开始.

Monday, 1 January 2011
Tuesday, 2 January 2011
Wednesday, 3 January 2011
Thursday, 4 January 2011
Friday, 5 January 2011
Saturday, 6 January 2011
Sunday, 7 January 2011

例如,我希望从2月22日开始接下来的七天.不知道如何处理这个问题.

Answer 1

这似乎是你正在寻找的:

function GetDates(startDate, daysToAdd) {
    var aryDates = [];

    for (var i = 0; i <= daysToAdd; i++) {
        var currentDate = new Date();
        currentDate.setDate(startDate.getDate() + i);
        aryDates.push(DayAsString(currentDate.getDay()) + ", " + currentDate.getDate() + " " + MonthAsString(currentDate.getMonth()) + " " + currentDate.getFullYear());
    }

    return aryDates;
}

function MonthAsString(monthIndex) {
    var d = new Date();
    var month = new Array();
    month[0] = "January";
    month[1] = "February";
    month[2] = "March";
    month[3] = "April";
    month[4] = "May";
    month[5] = "June";
    month[6] = "July";
    month[7] = "August";
    month[8] = "September";
    month[9] = "October";
    month[10] = "November";
    month[11] = "December";

    return month[monthIndex];
}

function DayAsString(dayIndex) {
    var weekdays = new Array(7);
    weekdays[0] = "Sunday";
    weekdays[1] = "Monday";
    weekdays[2] = "Tuesday";
    weekdays[3] = "Wednesday";
    weekdays[4] = "Thursday";
    weekdays[5] = "Friday";
    weekdays[6] = "Saturday";

    return weekdays[dayIndex];
}

var startDate = new Date();
var aryDates = GetDates(startDate, 7);
console.log(aryDates);?
?

结果(截至今天):

["Thursday, 5 April 2012",
 "Friday, 6 April 2012", 
 "Saturday, 7 April 2012", 
 "Sunday, 8 April 2012", 
 "Monday, 9 April 2012", 
 "Tuesday, 10 April 2012", 
 "Wednesday, 11 April 2012", 
 "Thursday, 12 April 2012"]

这是一个工作小提琴.

Answer 2

这是我使用Moment.js 的解决方案

未来 7 天

let days = [];
let daysRequired = 7

for (let i = 1; i <= daysRequired; i++) {
  days.push( moment().add(i, 'days').format('dddd, Do MMMM YYYY') )
}

console.log(days)

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>

以防万一，如果您需要前 7 天

let days = [];
let daysRequired = 7

for (let i = daysRequired; i >= 1; i--) {
  days.push( moment().subtract(i, 'days').format('dddd, Do MMMM YYYY') )
}

console.log(days)

<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.18.1/moment.min.js"></script>