如何在List <List <keyvaluepair <string,double >>>中选择keyvaluepair列表并修改它们的值？C#

Question

现在问题非常困难.现在这是我的主要清单

List<List<KeyValuePair<string, double>>> dblWordFreqByCluster = new List<List<KeyValuePair<string, double>>>();

所以让我们给出示例列表

(house,40),(home,20),(monitor,40)
(home,10),(work,60),(monitor,30)
(school,70),(home,10),(word,20)

所以每一行都是a,List<KeyValuePair<string, double>>并且有一个包含所有这些行的最大列表.

我想要做的是选择每个单词的值,它们的总和,然后在整个列表中划分单词计数.因此,在此修改后,列表将成为以下内容

(house,40),(home,40/3),(monitor,70/2)
(home,40/3),(work,60),(monitor,70/2)
(school,70),(home,40/3),(word,20)

这意味着获取每个键的平均值并更新每个键值.

C#4.0 WPF

Answer 1

Linq非常容易.首先,计算每个密钥的平均值:

var averages =
    (from list in dblWordFreqByCluster
     from kvp in list
     group kvp by kvp.Key into g
     select new 
     {
         Key = g.Key,
         Avg = g.Average(kvp => kvp.Value)
     }).ToDictionary(x => x.Key, x => x.Avg);

然后更新列表.由于KeyValuePair是不可变的,您需要用新的项目替换项目:

foreach (var list in dblWordFreqByCluster)
{
    for (int i = 0; i < list.Count; i++)
    {
        string key = list[i].Key;
        list[i] = new KeyValuePair<string, double>(key, averages[key]);
    }
}