boost :: signals2 slot作为非静态函数成员？

Question

我最近一直在boost::signals2为学习目的而玩,我想知道我是否可以将信号连接到一个类中的非静态插槽(就像我在Qt中那样).考虑以下:

class Worker {
    typedef boost::signals2::signal<void (const std::string &)> SendMessage;
public:
    typedef SendMessage::slot_type SendMessageSlotType;
    boost::signals2::connection connect(const SendMessageSlotType &slot) {
        return send_message.connect(slot);
    }
private:
    SendMessage send_message;
};

class Controller {
public:
    Controller() {
        worker.connect(&Controller::print);
    }
private:
    static void print(const std::string &message) {
        std::cout << message << std::endl;
    }

    Worker worker;
};

现在我想创建Controller::print一个非静态成员.与boost::thread例如,这可以使用来实现boost::bind; 有没有办法做到这一点boost::signals2？

Answer 1

只是:

class Controller {
public:
    Controller() {
        worker.connect(boost::bind(&Controller::print, this, _1));
    }
private:
    void print(const std::string &message) {
        std::cout << message << std::endl;
    }

    Worker worker;
};