按顺序分组值

Question

我有一些像这样的桌子

row chequeNo
 1     15
 2     19
 3     20
 4     35
 5     16

我需要得到这样的结果

row  from   to    
 1    15    16     
 2    19    20    
 3    35    35

所以我需要一组chequeNo值,这些值将是连续的,没有任何中断.chequeNo是独特的专栏.另外,它应该使用一个sql select查询,因为我没有权限创建除select查询之外的任何sql结构.

那有可能吗？

将不胜感激任何帮助

Answer 1

您可以在这里使用Aketi Jyuuzou的技术Tabibitosan:

SQL> create table mytable (id,chequeno)
  2  as
  3  select 1, 15 from dual union all
  4  select 2, 19 from dual union all
  5  select 3, 20 from dual union all
  6  select 4, 35 from dual union all
  7  select 5, 16 from dual
  8  /

Table created.

SQL> with tabibitosan as
  2  ( select chequeno
  3         , chequeno - row_number() over (order by chequeno) grp
  4      from mytable
  5  )
  6  select row_number() over (order by grp) "row"
  7       , min(chequeno) "from"
  8       , max(chequeno) "to"
  9    from tabibitosan
 10   group by grp
 11  /

       row       from         to
---------- ---------- ----------
         1         15         16
         2         19         20
         3         35         35

3 rows selected.

问候,
Rob.

Answer 2

这应该适用于 Oracle 10（仅在 Oracle 11 上进行了测试）

select group_nr + 1,
       min(chequeno) as start_value,
       max(chequeno) as end_value
from (
  select chequeno,
         sum(group_change_flag) over (order by rn) as group_nr
  from (
    select row_number() over (order by chequeno) as rn,
           chequeno, 
           case 
             when chequeno - lag(chequeno,1,chequeno) over (order by chequeno) <= 1 then 0 
             else 1
           end as group_change_flag
    from foo
  ) t1
) t2
group by group_nr
order by group_nr

（它应该与任何支持标准 SQL 窗口函数的 DBMS 一起使用，例如 PostgreSQL、DB2、SQL Server 2012）