Knockoutjs:如何在不使用if的情况下过滤foreach绑定

Question

有没有办法使用自定义绑定实现下面的语句,以消除if绑定:

<div data-bind="foreach: $root.customersVM.customers">
    @Html.Partial("_Customer")
    <div data-bind="foreach: $root.ordersVM.orders">
        <!-- ko if: customer() == $parent.id() -->
        @Html.Partial("_Order")
        <!-- /ko -->
    </div>
</div>

或者以另一种方式说:在Knockout.js foreach的答案中有人知道Way 2 :但只有当比较为真时？

Answer 1

如何创建另一个执行过滤的计算机或函数,并且可以迭代而不是迭代订单？

HTML

<div data-bind="with: filteredCustomers('smith')">
    <span data-bind="text: name"></span>
</div>

<div data-bind="foreach: customers">
    <span data-bind="text: name"></span>
</div>

<div data-bind="foreach: filteredOrders(4)">
    <span data-bind="text: id"></span>
</div>

<div data-bind="foreach: orders">
    <span data-bind="text: id"></span>
</div>

<button data-bind="click: function() {customers.push({name:'Smith'});}">Add customer</button>
<button data-bind="click: function() {orders.push({id:4});}">Add order</button>

使用Javascript:

var vm = {
    customers: ko.observableArray([
        {name: 'Smith'}, {name: 'Williams'}, {name: 'Brown'}, {name: 'Miller'}
    ]),
    orders: ko.observableArray([
        {id: 1}, {id: 2}, {id: 3}, {id: 4}, {id: 4}
    ])
};

// return first hit (unique ID)
vm.filteredCustomers = function(name) {
   return ko.utils.arrayFirst(this.customers(), function(customer) {
      return (customer.name.toLowerCase() === name.toLowerCase());
   });
};

// return all hits
vm.filteredOrders = function(id) {
   return ko.utils.arrayFilter(this.orders(), function(order) {
      return (order.id === id);
   });
};

ko.applyBindings(vm);