jQuery - 保持js数组和DOM对象列表同步?

Til*_*ter 6 jquery dom

假设我有一系列对象

[{href: 'some_uri', 'class': 'this-css-class'}, {href: 'another_uri', 'class': 'that-css-class'}]

我现在想将其映射到html列表:

<ul>
  <li class="this-css-class"><a href="some_uri">some_uri</a></li>
  <li class="that-css-class"><a href="another_uri">another_uri</a></li>
</ul>
Run Code Online (Sandbox Code Playgroud)

假设我向我的数组中添加了另一个对象,我想<li>在列表中添加一个新对象.相反,当我$('.that-css-class').remove()列出其中一个列表项时,我希望它也可以在数组中消失.

我想把它保存在jQuery中,因为我不想在项目中引入另一个框架.

非常感谢,这一直在我的脑海中.谢谢.

Adr*_*ler 1

类似的东西?: http: //jsfiddle.net/RZPNG/4/

var datas = [
    {href: 'some_uri', 'class': 'this-css-class'}, 
    {href: 'another_uri', 'class': 'that-css-class'}
],
  ul = $('ul');

$.each(datas, function(key, value) { // initialize list
    createElement(value);
});

function createElement(elem) {
    ul.append($('<li class=' + elem.class + '><a href="' + elem.href + '">' + elem.href + '</a></li>'));
}

function addElement(elem) {
    datas.push(elem);
    createElement(elem);
}

function removeElement(i) {
    datas.splice(i, 1);
    $(ul.find('li').get(i)).remove();
}

addElement({href: 'foo', 'class': 'bar'});
removeElement(1);
Run Code Online (Sandbox Code Playgroud)

选择方式:

var datas = [
    {href: 'some_uri', 'class': 'this-css-class'}, 
    {href: 'another_uri', 'class': 'that-css-class'}
],
  ul = $('ul');

$.each(datas, function(key, value) { // initialize list
    createElement(value);
});

function createElement(elem) {
    ul.append($('<li class=' + elem.class + '><a href="' + elem.href + '">' + elem.href + '</a></li>'));
}

function addElement(elem) {
    datas.push(elem);
    createElement(elem);
}

function removeElement(selector) {
    datas.splice(findElement(selector), 1);
    $(ul.find('li.' + selector)).remove();
}

function findElement(selector) {
    for (var i in datas) {
        if (datas[i].class === selector) {
           return i;   
        }
    }                
}

addElement({href: 'foo', 'class': 'bar'});
removeElement('that-css-class');
Run Code Online (Sandbox Code Playgroud)