Spring 3.1 LDAP身份验证过程:凭据"良好"时出现"错误凭据"消息

Question

Spring 3.1 Tomcat 6.*

我正在制作一个Spring 3.1 webapp,用LDAP进行身份验证.

我使用我编写的JNDI样式的Java程序测试了LDAP凭据(用户名,密码,ldap URL,搜索模式)(引用如下).该程序工作,转储所有用户属性,包括密码,似乎在LDAP服务器上加密.

当我尝试在Spring 3.1中使用相同的凭据登录时,我收到错误消息"Bad Credentials".

我在日志中收到此消息:

DEBUG [org.springframework.security.authentication.ProviderManager:authenticate] (ProviderManager.java:152) - Authentication attempt using org.springframework.security.ldap.authentication.LdapAuthenticationProvider
DEBUG [org.springframework.security.ldap.authentication.AbstractLdapAuthenticationProvider:authenticate] (AbstractLdapAuthenticationProvider.java:51) - Processing authentication request for user: John.A.Smith
DEBUG [org.springframework.security.ldap.authentication.BindAuthenticator:bindWithDn] (BindAuthenticator.java:108) - Attempting to bind as uid=John.A.Smith,ou=People,o=acme.com,o=acme.com
DEBUG [org.springframework.security.ldap.DefaultSpringSecurityContextSource$1:setupEnvironment] (DefaultSpringSecurityContextSource.java:76) - Removing pooling flag for user uid=John.A.Smith,ou=People,o=acme.com,o=acme.com
DEBUG [org.springframework.security.ldap.authentication.BindAuthenticator:handleBindException] (BindAuthenticator.java:152) - Failed to bind as uid=John.A.Smith,ou=People,o=acme.gov: org.springframework.ldap.AuthenticationException: [LDAP: error code 32 - No Such Object]; nested exception is javax.naming.AuthenticationException: [LDAP: error code 32 - No Such Object]
DEBUG [org.springframework.security.web.authentication.AbstractAuthenticationProcessingFilter:unsuccessfulAuthentication] (AbstractAuthenticationProcessingFilter.java:340) - Authentication request failed: org.springframework.security.authentication.BadCredentialsException: Bad credentials

在我的*-security.xml中,我尝试使用标签进行密码比较和编码,但它没有帮助.我尝试使用md4,md5,plaintext,sha,sha-256,{ssha},{sha}无济于事.

   <s:authentication-manager>
        <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People,o=noaa.gov" >
          <s:password-compare hash="md5">
            <s:password-encoder hash="md5"/>
          </s:password-compare>
        </s:ldap-authentication-provider>
      </s:authentication-manager>

我的网络组织是一个庞大,缓慢,官僚组织.我有没有办法告诉他们使用什么编码,如果有的话,不联系他们？

我可以查看的任何想法吗？

这是我上次尝试的*-security.xml以及我能够连接的Java LDAP演示

谢谢.

我的*-security.xml文件:

<beans xmlns="http://www.springframework.org/schema/beans"  
  xmlns:s="http://www.springframework.org/schema/security"  
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
  xsi:schemaLocation="http://www.springframework.org/schema/beans  
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd  
    http://www.springframework.org/schema/security  
    http://www.springframework.org/schema/security/spring-security-3.1.xsd">  



  <s:http auto-config="true" use-expressions="true">  
    **<s:intercept-url pattern="/welcome*" access="isAuthenticated()" />** 
    <s:form-login login-page="/login" default-target-url="/welcome"  
      authentication-failure-url="/loginfailed" />  
    <s:logout logout-success-url="/logout" />  
  </s:http>  



  <s:ldap-server url = "ldap://ldap-itc.sam.acme.com:636/o=acme.com"/>  

  <s:authentication-manager>
    <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People,o=noaa.gov" />
  </s:authentication-manager>

</beans>  

以下是使用相同凭据的JNDI样式LDAP Java程序:

import javax.naming.*;  
import javax.naming.directory.*;  
import java.util.*;  
import java.sql.*;  

public class LDAPDEMO {  

    public static void main(String args[]) {  

        String lcf                = "com.sun.jndi.ldap.LdapCtxFactory";  
        String ldapurl            = "ldap://ldap-itc.sam.acme.com:636/o=acme.com";  
        String loginid            = "John.A.Smith";  
        String password           = "passowordforjohn";  
        DirContext ctx            = null;  
        Hashtable env             = new Hashtable();  
        Attributes attr           = null;  
        Attributes resultsAttrs   = null;  
        SearchResult result       = null;  
        NamingEnumeration results = null;  
        int iResults              = 0;  


        env.put(Context.INITIAL_CONTEXT_FACTORY, lcf);  
        env.put(Context.PROVIDER_URL, ldapurl);  
        env.put(Context.SECURITY_PROTOCOL, "ssl");  
        env.put(Context.SECURITY_AUTHENTICATION, "simple");  
        env.put(Context.SECURITY_PRINCIPAL, "uid=" + loginid + ",ou=People,o=acme.com");  
        env.put(Context.SECURITY_CREDENTIALS, password);  
        try {  

            ctx     = new InitialDirContext(env);  
            attr    = new BasicAttributes(true);  
            attr.put(new BasicAttribute("uid",loginid));  
            results = ctx.search("ou=People",attr);  

            while (results.hasMore()) {  
                result       = (SearchResult)results.next();  
                resultsAttrs = result.getAttributes();  

                for (NamingEnumeration enumAttributes  = resultsAttrs.getAll(); enumAttributes.hasMore();) {  
                    Attribute a = (Attribute)enumAttributes.next();  
                    System.out.println("attribute: " + a.getID() + " : " + a.get().toString());  


                }// end for loop  

                iResults++;  
            }// end while loop  

            System.out.println("iResults == " + iResults);  

        }// end try  
        catch (Exception e) {  
            e.printStackTrace();  
        }  



    }// end function main()  
}// end class LDAPDEMO  

---

解

---

Luke Taylor的评论帮助我完成了配置工作:

您的配置错误,因为您在LDAP服务器URL中有"o = acme.com",并且在用户DN模式中也使用"o = acme.com".

我从DN模式中取出了"o = acme.com"并且LDAP工作了.我最初将"o = acme.com"放在LDAP URL和DN模式中,因为我是Spring 3.1和LDAP的新手,这类似于它在LDAP的JNDI版本中的实现方式.我根据我要替换的遗留代码编写的演示.

这是我的*-security.xml的最终工作版本

<beans xmlns="http://www.springframework.org/schema/beans"  
  xmlns:s="http://www.springframework.org/schema/security"  
  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  
  xsi:schemaLocation="http://www.springframework.org/schema/beans  
    http://www.springframework.org/schema/beans/spring-beans-3.0.xsd  
    http://www.springframework.org/schema/security  
    http://www.springframework.org/schema/security/spring-security-3.1.xsd">  



  <s:http auto-config="true" use-expressions="true">  
    **<s:intercept-url pattern="/welcome*" access="isAuthenticated()" />** 
    <s:form-login login-page="/login" default-target-url="/welcome"  
      authentication-failure-url="/loginfailed" />  
    <s:logout logout-success-url="/logout" />  
  </s:http>  



  <s:ldap-server url = "ldap://ldap-itc.sam.acme.com:636/o=acme.com"/>  

  <s:authentication-manager>
    <s:ldap-authentication-provider user-dn-pattern="uid={0},ou=People" />
  </s:authentication-manager>

</beans>  

我将探讨他的其他评论,看看我是否可以重新输入密码或者是否需要.

Answer 1

您的 Java 示例使用标准绑定身份验证，但您已将 Spring Security 配置设置为对用户密码执行LDAP 比较操作。这将失败，因为 LDAP 服务器没有使用与 Spring Security 的 MD5 编码器相同的密码编码格式。为了使比较操作成功，存储的值必须与发送到目录的字符串匹配。在大多数情况下，您希望使用标准 LDAP（绑定）身份验证。您可能需要为身份验证提供程序使用 bean 配置。尝试使用：

<s:ldap-server id="contextSource" url="ldap://ldap-itc.sam.acme.com:636/o=acme.com"/>

<bean id="ldapAuthProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider">
 <constructor-arg>
   <bean class="org.springframework.security.ldap.authentication.BindAuthenticator">
     <constructor-arg ref="contextSource"/>
     <property name="userDnPatterns">
       <list><value>uid={0},ou=People</value></list>
     </property>
   </bean>
 </constructor-arg>
 <constructor-arg>
   <bean class="org.springframework.security.ldap.authentication.NullLdapAuthoritiesPopulator"/>
 </constructor-arg>
  <property name="authoritiesMapper">
    <bean class="class="org.springframework.security.core.authority.mapping">
       <property name="defaultAuthority" value="ROLE_USER" />
    </bean>
  </property>   
</bean>

<s:authentication-manager>
  <s:authentication-manager ref="ldapAuthProvider" />
</s:authentication-manager>

我建议您还阅读参考手册的 LDAP 章节。

此外，如果您想了解身份验证失败的原因，最好的查找位置是 LDAP 服务器本身的日志。如果您没有完全访问权限，请了解其设置方式并使用您拥有完全控制权的本地服务器（例如 OpenLDAP）。