Unix代码想要复制模板文件并替换复制文件中模板文件中的字符串

Question

我有2个文件:

File_1.txt:

John
Mary
Harry
Bill

File_2.txt:

My name is ID, and I am on line NR of file 1.

我想创建四个看起来像这样的文件:

Output_file_1.txt:

My name is John, and I am on line 1 of file 1.

Output_file_2.txt:

My name is Mary, and I am on line 2 of file 1.

Output_file_3.txt:

My name is Harry, and I am on line 3 of file 1.

Output_file_4.txt:

My name is Bill, and I am on line 4 of file 1.

通常我会使用以下sed命令来执行此操作:

for q in John Mary Harry Bill
do  
sed 's/ID/'${q}'/g' File_2.txt > Output_file.txt
done

但这只会替换名称的ID,而不包括File_1.txt的行号.不幸的是,我的bash技能没有比这更进一步......对于包含文件1和2的命令的任何提示或建议？我确实需要包含文件1,因为实际上文件比这个例子大得多,但我想如果我知道如何用这个希望更简单的例子来解决其余的代码......很多提前致谢!

Answer 1

怎么样:

n=1
while read q
  do  
  sed -e 's/ID/'${q}'/g' -e "s/NR/$n/" File_2.txt > Output_file_${n}.txt
  ((n++))
done < File_1.txt