如何排序日期对象列表？

Question

如何排序日期对象列表？例如,我有未分类的日期对象列表.如何从此列表中获取最大/最小值？

Answer 1

使用列表排序方法:

In [1]: from datetime import date, timedelta

In [2]: a=[date.today(), date.today() + timedelta(days=1), date.today() - timedelta(days=1)]

In [3]: a
Out[3]: 
[datetime.date(2012, 3, 28),
 datetime.date(2012, 3, 29),
 datetime.date(2012, 3, 27)]

In [4]: a.sort()

In [5]: a
Out[5]: 
[datetime.date(2012, 3, 27),
 datetime.date(2012, 3, 28),
 datetime.date(2012, 3, 29)]

In [6]: a[0] # min
Out[6]: datetime.date(2012, 3, 27)

In [7]: a[-1] # max
Out[7]: datetime.date(2012, 3, 29)

更多关于如何排序.

Answer 2

list.sort(key=lambda item:item['date'], reverse=True)