php内的javascript

Question

我怎么能在PHP里面写一个javascript警报？例如,如果我想在此if条件中弹出一个javascript警报我该怎么办？

if(isset($_POST['downloadkey'])){
                $key = $_POST['downloadkey'];
                if($key != $data['download_key']){
                    echo 'Your key is wrong.';
                    echo '<script type="text/javascript"> alert(Your downlaod key is wrong, Please try again!);</script>';
                }
            }

提前致谢

Answer 1

你忘了在警告中用引号括起字符串.

"你的下载键错了,请再试一次!" 是一个字符串

if(isset($_POST['downloadkey'])){
                $key = $_POST['downloadkey'];
                if($key != $data['download_key']){
                    echo 'Your key is wrong.';
                    echo '<script type="text/javascript"> alert("Your downlaod key is wrong, Please try again!");</script>';
                }
            }