计算一年中每个月的记录

Question

我有一个总共没有1000条记录的表.它有以下结构:

EMP_ID EMP_NAME PHONE_NO   ARR_DATE
1        A        545454 2012/03/12

我想计算2012年每个月的记录数

有什么方法可以一次解决我的问题吗？

我试过了:

select count(*) 
from table_emp 
where year(ARR_DATE) = '2012' and month(ARR_DATE) = '01'

Answer 1

SELECT    COUNT(*) 
FROM      table_emp 
WHERE     YEAR(ARR_DATE) = '2012' 
GROUP BY  MONTH(ARR_DATE)

Answer 2

这将为您提供2012年每月的点数;

SELECT MONTH(ARR_DATE) MONTH, COUNT(*) COUNT
FROM table_emp
WHERE YEAR(arr_date)=2012
GROUP BY MONTH(ARR_DATE);

在这里演示.

Answer 3

试试这个查询:

SELECT 
  SUM(CASE datepart(month,ARR_DATE) WHEN 1 THEN 1 ELSE 0 END) AS 'January',
  SUM(CASE datepart(month,ARR_DATE) WHEN 2 THEN 1 ELSE 0 END) AS 'February',
  SUM(CASE datepart(month,ARR_DATE) WHEN 3 THEN 1 ELSE 0 END) AS 'March',
  SUM(CASE datepart(month,ARR_DATE) WHEN 4 THEN 1 ELSE 0 END) AS 'April',
  SUM(CASE datepart(month,ARR_DATE) WHEN 5 THEN 1 ELSE 0 END) AS 'May',
  SUM(CASE datepart(month,ARR_DATE) WHEN 6 THEN 1 ELSE 0 END) AS 'June',
  SUM(CASE datepart(month,ARR_DATE) WHEN 7 THEN 1 ELSE 0 END) AS 'July',
  SUM(CASE datepart(month,ARR_DATE) WHEN 8 THEN 1 ELSE 0 END) AS 'August',
  SUM(CASE datepart(month,ARR_DATE) WHEN 9 THEN 1 ELSE 0 END) AS 'September',
  SUM(CASE datepart(month,ARR_DATE) WHEN 10 THEN 1 ELSE 0 END) AS 'October',
  SUM(CASE datepart(month,ARR_DATE) WHEN 11 THEN 1 ELSE 0 END) AS 'November',
  SUM(CASE datepart(month,ARR_DATE) WHEN 12 THEN 1 ELSE 0 END) AS 'December',
  SUM(CASE datepart(year,ARR_DATE) WHEN 2012 THEN 1 ELSE 0 END) AS 'TOTAL'
FROM
    sometable
WHERE
  ARR_DATE BETWEEN '2012/01/01' AND '2012/12/31'