JAXB Java生成XML,为什么小写?

use*_*962 15 java xml jaxb

当我运行此代码时:

import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;

public class JavaToXMLDemo {
  public static void main(String[] args) throws Exception {
    JAXBContext context = JAXBContext.newInstance(Employee.class);

    Marshaller m = context.createMarshaller();
    m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    Employee object = new Employee();
    object.setCode("CA");
    object.setName("Cath");
    object.setSalary(300);

    m.marshal(object, System.out);

  }
}

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
class Employee {
  private String code;

  private String name;

  private int salary;

  public String getCode() {
    return code;
  }

  public void setCode(String code) {
    this.code = code;
  }

  public String getName() {
    return name;
  }

  public void setName(String name) {
    this.name = name;
  }

  public int getSalary() {
    return salary;
  }

  public void setSalary(int population) {
    this.salary = population;
  }
}
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我明白了

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<employee>
    <code>CA</code>
    <name>Cath</name>
    <salary>300</salary>
</employee>
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这是正确的,所以我的问题是为什么它将员工改为员工?是否可以使用大写E而不是员工进行打印?

这就是我真正想要的:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Employee>
    <code>CA</code>
    <name>Cath</name>
    <salary>300</salary>
</Employee>
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谢谢!

bdo*_*han 25

您看到的行为是标准JAXB(JSR-222) XML名称到Java名称转换算法的结果.

您可以使用@XmlRootElement注释指定名称:

@XmlRootElement(name="Employee")
@XmlAccessorType(XmlAccessType.FIELD)
class Employee {
    ...
}
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我是EclipseLink JAXB(MOXy)的主管,我们有一个扩展,允许您覆盖您可能感兴趣的默认名称转换算法:


FAt*_*oon 5

对于特定元素......

@XmlElement( name = "Code")
private String code;
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对象....

@XmlRootElement(name="Employee")
public class Employee{ ...
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