我有一张桌子,里面装满了物品和价格.我想抓住3个价格最高的商品的总和.
我想也许,SELECT SUM(items.price) FROM items ORDER BY items.price LIMIT 3
但似乎没有做到这一点.这可能吗?谢谢!
Ker*_*elM 35
select sum(price) from (select items.price from items order by items.price desc limit 3) as subt;
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LIMIT
影响查询返回的行数,SUM只返回一行.基于此主题,您可能想尝试:
SELECT sum(price)
FROM (SELECT price
FROM items
ORDER BY price DESC
LIMIT 3
) AS subquery;
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