Jul*_*eto 13 javascript php jquery
我有这个代码.
<html>
<head>
<style type="text/css">
body{background:#666666;}
div{border:1px solid red;}
</style>
</head>
<body>
<?php
$con = mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("juliver", $con);
$result = mysql_query("SELECT * FROM hi");
while($row = mysql_fetch_array($result))
{
echo '<img src="'.$row['name'].'" />';
echo "<div>".$row['name']."</div>";
echo "<div>".$row['title']."</div>";
echo "<div>".$row['description']."</div>";
echo "<div>".$row['link']."</div>";
echo "<br />";
}
mysql_close($con);
?>
</body>
</html>
上面的代码有效.
现在,我想插入此内容
echo '<img src="'.$row['name'].'" />';
echo "<div>".$row['name']."</div>";
echo "<div>".$row['title']."</div>";
echo "<div>".$row['description']."</div>";
echo "<div>".$row['link']."</div>";
echo "<br />";
进入指定的div或html中的其他元素,例如,我将插入此
echo '<img src="'.$row['name'].'" />';
进入html元素.
我不知道该怎么做,请帮帮我.谢谢
Juliver
参考基本的。
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john@example.com')";
if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
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