我需要以树型创建产品目录.
每个树节点都以ID(字符串)表示,树数据上的函数只有2:
getChild(string ID),给一个ID,得到孩子(不需要包括孩子的孩子),如果ID为null,则获取所有根节点 getParent(string ID),如果有,则返回父ID,如果是root,则返回null由于一旦树决定了,不会改变,所以我认为把所有代码放在静态中会是最好的.所以我开始尝试使用Dictionary
"id": {parent:ID, child:[id2, id3, id4....]}
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由于大约1000多个目录,我发现我很快搞砸了自己,在静态数据中出现了很多错误,并使最终结果可用.此外,现在我只写了几十个,代码看起来像混乱.
请建议以高性能创建这个简单的目录树.谢谢
Sim*_*Var 57
只是做一个课程.
更新:
class TreeNode : IEnumerable<TreeNode>
{
private readonly Dictionary<string, TreeNode> _children =
new Dictionary<string, TreeNode>();
public readonly string ID;
public TreeNode Parent { get; private set; }
public TreeNode(string id)
{
this.ID = id;
}
public TreeNode GetChild(string id)
{
return this._children[id];
}
public void Add(TreeNode item)
{
if (item.Parent != null)
{
item.Parent._children.Remove(item.ID);
}
item.Parent = this;
this._children.Add(item.ID, item);
}
public IEnumerator<TreeNode> GetEnumerator()
{
return this._children.Values.GetEnumerator();
}
IEnumerator IEnumerable.GetEnumerator()
{
return this.GetEnumerator();
}
public int Count
{
get { return this._children.Count; }
}
}
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静态定义的用法非常简单:
var tree = new TreeNode("Root")
{
new TreeNode("Category 1")
{
new TreeNode("Item 1"),
new TreeNode("Item 2"),
new TreeNode("Item 3"),
},
new TreeNode("Category 2")
{
new TreeNode("Item 1"),
new TreeNode("Item 2"),
new TreeNode("Item 3"),
new TreeNode("Item 4"),
}
};
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编辑
更多功能,更容易创建......
public static TreeNode BuildTree(string tree)
{
var lines = tree.Split(new[] { Environment.NewLine },
StringSplitOptions.RemoveEmptyEntries);
var result = new TreeNode("TreeRoot");
var list = new List<TreeNode> { result };
foreach (var line in lines)
{
var trimmedLine = line.Trim();
var indent = line.Length - trimmedLine.Length;
var child = new TreeNode(trimmedLine);
list[indent].Add(child);
if (indent + 1 < list.Count)
{
list[indent + 1] = child;
}
else
{
list.Add(child);
}
}
return result;
}
public static string BuildString(TreeNode tree)
{
var sb = new StringBuilder();
BuildString(sb, tree, 0);
return sb.ToString();
}
private static void BuildString(StringBuilder sb, TreeNode node, int depth)
{
sb.AppendLine(node.ID.PadLeft(node.ID.Length + depth));
foreach (var child in node)
{
BuildString(sb, child, depth + 1);
}
}
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用法:
var tree = TreeNode.BuildTree(@"
Cat1
Sub1
Item1
Item2
Item3
Sub2
Item1
Item2
Cat2
Sub1
Sub2
Item1
Item2
Sub3
Item1
Cat3
Cat4");
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