Oracle Pl/SQL:循环遍历XMLTYPE节点

Question

我有一个XMLTYPE,其中包含以下内容:

<?xml version="1.0"?>
    <users>
        <user>
            <name>user1</name>
        </user>
        <user>
            <name>user2</name>
        </user>
        <user>
            <name>user3</name>
        </user>
    </users>

如何通过所有元素"user"循环PL/SQL？谢谢

Answer 1

您可以使用EXTRACT和遍历元素XMLSequence(并将XML拆分为不同的块 - 这里是用户),如下所示:

SQL> SELECT extractvalue(column_value, '/user/name') "user"
  2    FROM TABLE(XMLSequence(XMLTYPE(
  3                 '<?xml version="1.0"?>
  4                     <users>
  5                         <user>
  6                             <name>user1</name>
  7                         </user>
  8                         <user>
  9                             <name>user2</name>
 10                         </user>
 11                         <user>
 12                             <name>user3</name>
 13                         </user>
 14                     </users>').extract('/users/user'))) t;

user
--------
user1
user2
user3

Answer 2

你可以使用XQuery.查看下面的选择声明.v_xml_doc是包含XML数据的XMLTYPE变量.

select name
from   XMLTable('for $i in /users/user
                            return $i'
                            passing   v_xml_doc
                            columns   name varchar2(200) path 'name'
               )

Answer 3

这个怎么样:

PROCEDURE xmltest IS
  v_userlist XMLType;
  v_count NUMBER(38) := 1;
BEGIN
  /* define XML variable */
  v_userlist := XMLType('<?xml version="1.0"?>
    <users>
        <user>
            <name>user1</name>
        </user>
        <user>
            <name>user2</name>
        </user>
        <user>
            <name>user3</name>
        </user>
    </users>');

  /* for each user, print out their name (each element can be extracted using xpath '//user[1]' '//user[2]' etc) */
  WHILE v_userlist.existsNode('//user[' || v_count || ']') = 1 LOOP
    dbms_output.put_line(v_userlist.extract('//user[' || v_count || ']/name/text()').getStringVal());
    v_count := v_count + 1;
  END LOOP;
END;