从远程服务器或URL复制文件

Kri*_*ris 20 php copy file

我有以下代码:

$file = 'http://3.bp.blogspot.com/-AGI4aY2SFaE/Tg8yoG3ijTI/AAAAAAAAA5k/nJB-mDhc8Ds/s400/rizal001.jpg';
$newfile = '/img/submitted/yoyo.jpg';

if ( copy($file, $newfile) ) {
    echo "Copy success!";
}else{
echo "Copy failed.";
}
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它总是输出"复制失败"

copy(/img/submitted/yoyo.jpg) [function.copy]: failed to open stream: No such file or directory
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我的目录设置为777.

有任何想法吗?谢谢!

Mar*_*iek 58

虽然copy()将接受URL作为参数,但它可能会出现目标的URL .

您是否尝试过指定输出文件的完整文件系统路径?我假设您没有尝试将新文件放到远程服务器上.

例如:

$file = 'http://3.bp.blogspot.com/-AGI4aY2SFaE/Tg8yoG3ijTI/AAAAAAAAA5k/nJB-mDhc8Ds/s400/rizal001.jpg';
$newfile = $_SERVER['DOCUMENT_ROOT'] . '/img/submitted/yoyo.jpg';

if ( copy($file, $newfile) ) {
    echo "Copy success!";
}else{
    echo "Copy failed.";
}
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以上对我来说很有效.


Ath*_*han 6

我在我的一个旧项目中发现了这个功能.

private function download_file ($url, $path) {

  $newfilename = $path;
  $file = fopen ($url, "rb");
  if ($file) {
    $newfile = fopen ($newfilename, "wb");

    if ($newfile)
    while(!feof($file)) {
      fwrite($newfile, fread($file, 1024 * 8 ), 1024 * 8 );
    }
  }

  if ($file) {
    fclose($file);
  }
  if ($newfile) {
    fclose($newfile);
  }
 }
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