Rap*_*sey 13 mysql group-by group-concat
我有一个带有请求的MySQL表
+--------+-------------+-----+
| req_id | req_name | ... |
+--------+-------------+-----+
| 1 | testrequest | ... |
+--------+-------------+-----+
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以及对此类请求进行投票的表格.
+--------+-----------+----------+
| req_id | vote_name | approved |
+--------+-----------+----------+
| 1 | User1 | 1 |
| 1 | User2 | 1 |
| 1 | User3 | 1 |
| 1 | User4 | 0 |
| 1 | User5 | 0 |
+--------+-----------+----------+
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我想要的那种观点:
+--------+-------------+---------------------+--------------+
| req_id | req_name | approved_by | rejected_by |
+--------+-------------+---------------------+--------------+
| 1 | testrequest | User1, User2, User3 | User4, User5 |
+--------+-------------+---------------------+--------------+
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然而,到目前为止,我只能做到这一点:
+--------+-------------+----------+---------------------+
| req_id | req_name | approved | by |
+--------+-------------+----------+---------------------+
| 1 | testrequest | YES | User1, User2, User3 |
| 1 | testrequest | NO | User4, User5 |
+--------+-------------+----------+---------------------+
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我使用的查询:
SELECT requests.req_id, req_name, CASE
WHEN approved THEN 'YES'
ELSE 'NO'
END AS approved, GROUP_CONCAT(vote_name ORDER BY vote_name ASC SEPARATOR ', ') AS by
FROM requests
LEFT JOIN votes ON requests.req_id = votes.req_id
GROUP BY requests.req_id, approved
ORDER BY requests.req_id DESC;
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所以我的问题是,如何在同一行中使用不同的值获得2个group_concats?
非常感谢!
Mos*_*cho 40
试试这个:
select r.req_id, r.req_name,
group_concat(if(approved, vote_name, null) separator ', ') approvedBy,
group_concat(if(approved, null, vote_name) separator ', ') rejectedBy
from requests r
left join votes v on r.req_id = v.req_id
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结果:
+--------+-------------+---------------------+--------------+
| REQ_ID | REQ_NAME | APPROVEDBY | REJECTEDBY |
+--------+-------------+---------------------+--------------+
| 1 | testrequest | User1, User2, User3 | User4, User5 |
+--------+-------------+---------------------+--------------+
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