每个主题每隔X天计算一次事件(在不规则的时间序列中)

Chr*_*ris 4 r

我有数据,我在计算护理事件(如ER访问).诀窍是,我无法计算每次访问,因为有时第二次或第三次访问实际上是先前问题的后续行动.因此,我已经被指定通过使用30天的"清洁期"或"停电期"来计算访问次数,这样,我会按患者(最小日期)查找第一个事件(访问1),我计算该事件,然后应用规则,以便不计算在第一个事件发生后30天内发生的任何访问.在那30天窗口过后,我可以开始寻找第二次访问(访问2),计算一次,然后再次应用30天黑色(不计算在访问#2后30天内发生的任何访问). ..洗,冲洗,重复......

我把一个非常草率的解决方案整合在一起,需要大量的保姆和手动检查步骤(见下文).我必须相信有更好的方法.救命!

data1 <- structure(list(ID = structure(c(2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 
3L, 4L, 4L, 4L, 4L, 4L), .Label = c("", "patient1", "patient2", 
"patient3"), class = "factor"), Date = structure(c(14610, 14610, 
14627, 14680, 14652, 14660, 14725, 15085, 15086, 14642, 14669, 
14732, 14747, 14749), class = "Date"), test = c(1L, 1L, 1L, 2L, 
1L, 1L, 2L, 3L, 3L, 1L, 1L, 2L, 2L, 2L)), .Names = c("ID", "Date", 
"test"), class = "data.frame", row.names = c(NA, 14L))

library(doBy) 
##     create a table of first events 
step1 <- summaryBy(Date~ID, data = data1, FUN=min) 
step1$Date30 <- step1$Date.min+30                                     
step2 <- merge(data1, step1, by.x="ID", by.y="ID") 
##     use an ifelse to essentially remove any events that shouldn't be counted 
step2$event <- ifelse(as.numeric(step2$Date) >= step2$Date.min & as.numeric(step2$Date) <= step2$Date30, 0, 1)
##     basically repeat steps above until I dont capture any more events
##  there just has to be a better way
data3 <- step2[step2$event==1,] 
data3<- data3[,1:3] 
step3 <- summaryBy(Date~ID, data = data3, FUN=min) 
step3$Date30 <- step3$Date.min+30 
step4 <- merge(data3, step3, by.x="ID", by.y="ID") 
step4$event <- ifelse(as.numeric(step4$Date) >= step4$Date.min & as.numeric(step4$Date) <= step4$Date30, 0, 1)
data4 <- step4[step4$event==1,]
data4<- data4[,1:3]
step5 <- summaryBy(Date~ID, data = data4, FUN=min)
step5$Date30 <- step5$Date.min+30
##     then I rbind the "keepers" 
##     in this case steps 1 and 3 above 
final <- rbind(step1,step3, step5) 
##     then reformat 
final <- final[,1:2] 
final$Date.min <- as.Date(final$Date.min,origin="1970-01-01") 
##     again, extremely clumsy, but it works...  HELP! :)
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G. *_*eck 6

这个解决方案是无环路的,只使用基数R.它产生一个逻辑向量ok,选择可接受的行data1.

ave 分别对每个患者运行指示的匿名功能.

我们定义一个状态向量,包括当前日期和没有考虑其他日期的期间的开始.每个日期由日期as.numeric(x)在哪里表示x. step获取状态向量和当前日期并更新状态向量. Reduce在数据上运行它,然后我们只采用最小和当前日期相同且当前日期不重复的结果.

step <- function(init, curdate) {
    c(curdate, if (curdate > init[2] + 30) curdate else init[2])
}

ok <- !!ave(as.numeric(data1$Date), paste(data1$ID), FUN = function(d) {
    x <- do.call("rbind", Reduce(step, d, c(-Inf, 0), acc = TRUE))
    x[-1,1] == x[-1,2] & !duplicated(x[-1,1])
})

data1[ok, ]
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