kds*_*253 4 .net c# xml linq-to-xml nested-groups
我正在尝试获得4个List深度列表集合List<List<List<List<int>>>>.从我的Xml看起来像
<root>
<Claim key="1" carrier="carA" zip="34343" pages="1"/>
<Claim key="2" carrier="carA" zip="34343" pages="2"/>
<Claim key="3" carrier="carB" zip="10505" pages="2"/>
<Claim key="4" carrier="carB" zip="10505" pages="4"/>
<Claim key="5" carrier="carB" zip="10505" pages="4"/>
</root>
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输出的结构应该是这样的
-all
-1
-34343
-carA
-1
-2
-34343
-carA
-2
-10505
-carB
-3
-4
-10505
-carB
-4
-5
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目标是首先根据节点属性按页数,然后按zip,然后按运营商对XML进行排序.然后,我需要遍历结果列表并按特定顺序处理每个声明.我无法获得3个嵌套组的语法.我已经完成了获得2个嵌套组,任何人都可以帮助我获得第三个.
到目前为止,这是我的代码.
var query = from claim in root.Elements("Claim")
group claim by claim.Attributes("Pages").First().Value into pageGroups
from zipGroups in
(from claim in pageGroups
group claim by int.Parse(claim.Attributes("CarrierZip").First().Value))
group zipGroups by pageGroups.Key;
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我不知道如何使用XML做到这一点,但如果你已经翻译的债权分为某种类型的数组Claim(例如,在代码中,claims是类型Claim[])和Claim类型有称为属性或字段Key,Carrier,Zip,和Pages这应该工作.
var dic = (from claim in claims
group claim by claim.Pages into pageGroup
select new {
Page = pageGroup.Key,
Entries =
(from zentry in pageGroup
group zentry by zentry.Zip into zipGroup
select new {
Zip = zipGroup.Key,
Entries =
(from centry in zipGroup
group centry by centry.Carrier into carrierGroup
select new { Carrier = carrierGroup.Key, Entries = carrierGroup.AsEnumerable() })
.ToDictionary(ent => ent.Carrier, ent => ent.Entries)
}).ToDictionary(ent => ent.Zip, ent => ent.Entries)
}).ToDictionary(ent => ent.Page, ent => ent.Entries);
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它不是很干净,但它有效.您可以选择具有给定页面,zip和运营商的声明,如下所示:
var myclaim = dic[4][34343]["carB"];
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我选择给你一种翻译方式,Dictionary<TKey, TValue>而不是List<T>因为翻译List失去了密钥,所以获取密钥(页面,邮政编码或载体)的唯一方法是遍历列表,这可能会变得丑陋和复杂.对不起,如果词典不适合你.