在nsstring中查找并替换所有内容

Question

我正在尝试查找单词列表,如果匹配我正在替换.打击代码有效,但如果匹配的单词出现多次,则不会替换.

我认为我需要使用while而不是if循环,但我无法使其工作.

我在挣扎请告诉我

    NSString *mymessage = @"for you for your information at you your at fate";

    NSMutableArray *full_text_list = [[NSMutableArray alloc]init];
    [full_text_list addObject:@"for"];
    [full_text_list addObject:@"for your information"];
    [full_text_list addObject:@"you"];
    [full_text_list addObject:@"at"];

    NSMutableArray *short_text_list = [[NSMutableArray alloc]init];
    [short_text_list addObject:@"4"];
    [short_text_list addObject:@"fyi"];
    [short_text_list addObject:@"u"];
    [short_text_list addObject:@"@"];

    for(int i=0;i<[full_text_list count];i++)
    {
        NSRange range = [mymessage rangeOfString:[full_text_list objectAtIndex:i]];

        if(range.location != NSNotFound) {
            NSLog(@"%@ found", [full_text_list objectAtIndex:i]);
            mymessage = [mymessage stringByReplacingCharactersInRange:range withString:[short_text_list objectAtIndex:i]];
        }


    }

Answer 1

你不必重新发明轮子; 可可为你做到了......

代码:

NSString* message = @"for you for your information at you your at fate";

NSMutableArray* aList = [[NSMutableArray alloc] initWithObjects:@"for your information",@"for",@"you ",@"at ",nil];
NSMutableArray* bList = [[NSMutableArray alloc] initWithObjects:@"fyi",@"4",@"u ",@"@ ",nil];

for (int i=0; i<[aList count];i++)
{
    message = [message stringByReplacingOccurrencesOfString:[aList objectAtIndex:i] 
                                                 withString:[bList objectAtIndex:i]];
}

NSLog(@"%@",message);

提示: 我们将用bList [0]替换aList [0]的每一个出现,用bList [1]替换aList [1],依此类推...... ;-)