jhd*_*vuk 35 string scala pattern-matching
我有以下内容:
serv match {
case "chat" => Chat_Server ! Relay_Message(serv)
case _ => null
}
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问题是有时我还会在serv字符串的末尾传递一个额外的参数,所以:
var serv = "chat.message"
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有没有办法可以匹配字符串的一部分,所以它仍然被发送到Chat_Server?
谢谢你的帮助,非常感谢:)
Kyl*_*yle 50
让模式匹配绑定到变量并使用guard来确保变量以"chat"开头
// msg is bound with the variable serv
serv match {
case msg if msg.startsWith("chat") => Chat_Server ! Relay_Message(msg)
case _ => null
}
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om-*_*nom 49
使用正则表达式;)
val Pattern = "(chat.*)".r
serv match {
case Pattern(chat) => "It's a chat"
case _ => "Something else"
}
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使用正则表达式,您甚至可以轻松地拆分参数和基本字符串:
val Pattern = "(chat)(.*)".r
serv match {
case Pattern(chat,param) => "It's a %s with a %s".format(chat,param)
case _ => "Something else"
}
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