将字符串解析为c样式字符数组的结构

Question

我有一个Visual Studio 2008 C++项目,我需要将字符串解析为c样式字符数组的结构.这样做最优雅/最有效的方法是什么？

这是我目前的(运作)解决方案:

struct Foo {
    char a[ MAX_A ];
    char b[ MAX_B ];
    char c[ MAX_C ];
    char d[ MAX_D ];
};

Func( const Foo& foo );

std::string input = "abcd@efgh@ijkl@mnop";
std::vector< std::string > parsed;
boost::split( parsed, input, boost::is_any_of( "@" ) );

Foo foo = { 0 };
parsed[ 1 ].copy( foo.a, MAX_A );
parsed[ 2 ].copy( foo.b, MAX_B );
parsed[ 3 ].copy( foo.c, MAX_C );
parsed[ 4 ].copy( foo.d, MAX_D );

Func( foo );

Answer 1

这是我(现已测试过)的想法:

#include <vector>
#include <string>
#include <cstring>

#define MAX_A 40
#define MAX_B 3
#define MAX_C 40
#define MAX_D 4

struct Foo {
    char a[ MAX_A ];
    char b[ MAX_B ];
    char c[ MAX_C ];
    char d[ MAX_D ];
};

template <std::ptrdiff_t N>
const char* extractToken(const char* inIt, char (&buf)[N])
{
    if (!inIt || !*inIt)
        return NULL;

    const char* end = strchr(inIt, '@');
    if (end)
    {
        strncpy(buf, inIt, std::min(N, end-inIt));
        return end + 1;
    } 
    strncpy(buf, inIt, N);
    return NULL;
}

int main(int argc, const char *argv[])
{
    std::string input = "abcd@efgh@ijkl@mnop";

    Foo foo = { 0 };

    const char* cursor = input.c_str();
    cursor = extractToken(cursor, foo.a);
    cursor = extractToken(cursor, foo.b);
    cursor = extractToken(cursor, foo.c);
    cursor = extractToken(cursor, foo.d);
}

[编辑]测试

添加一点测试代码

template <std::ptrdiff_t N>
std::string display(const char (&buf)[N])
{
    std::string result;
    for(size_t i=0; i<N && buf[i]; ++i)
       result += buf[i];
    return result; 
}

int main(int argc, const char *argv[])
{
    std::string input = "abcd@efgh@ijkl@mnop";

    Foo foo = { 0 };

    const char* cursor = input.c_str();
    cursor = extractToken(cursor, foo.a);
    cursor = extractToken(cursor, foo.b);
    cursor = extractToken(cursor, foo.c);
    cursor = extractToken(cursor, foo.d);

    std::cout << "foo.a: '" << display(foo.a) << "'\n";
    std::cout << "foo.b: '" << display(foo.b) << "'\n";
    std::cout << "foo.c: '" << display(foo.c) << "'\n";
    std::cout << "foo.d: '" << display(foo.d) << "'\n";
}

输出

foo.a: 'abcd'
foo.b: 'efg'
foo.c: 'ijkl'
foo.d: 'mnop'

在http://ideone.com/KdAhO上观看直播