例如,如何GroupId使用LINQ 对以下记录进行分组,并将每个组中的所有其他列相加?(从而将每个组中的所有行合并为一个)
var list = new List<Foo>()
{
new Foo() { GroupId = 0, ValueA = 10, ValueB = 100 },
new Foo() { GroupId = 1, ValueA = 30, ValueB = 700 },
new Foo() { GroupId = 1, ValueA = 40, ValueB = 500 },
new Foo() { GroupId = 2, ValueA = 80, ValueB = 300 },
new Foo() { GroupId = 2, ValueA = 20, ValueB = 200 },
new Foo() { GroupId = 2, ValueA = 20, ValueB = 200 }
};
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预期结果是:
| GroupId | ValueA | ValueB |
|---------|--------|--------|
| 0 | 10 | 100 |
| 1 | 70 | 1200 |
| 2 | 120 | 700 |
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Sno*_*ear 15
list.GroupBy(i => i.GroupId)
.Select(g => new { GroupId = g.Key,
ValueA = g.Sum(i => i.ValueA),
ValueB = g.Sum(i => i.ValueB)});
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或者只是为了好玩,你可以GroupBy使用它的重载在一个调用中完成它:
list.GroupBy(i => i.GroupId,
(key, groupedItems) => new {
GroupId = key,
ValueA = groupedItems.Sum(i => i.ValueA),
ValueB = groupedItems.Sum(i => i.ValueB),
});
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或者您可以使用Aggregate以避免多次迭代每个组:
list.GroupBy(i => i.GroupId)
.Select(g => g.Aggregate((i1, i2) => new Foo{ GroupId = i1.GroupId,
ValueA = i1.ValueA + i2.ValueA,
ValueB = i1.ValueB + i2.ValueB,
}));
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var query = list.GroupBy(x=> x.GroupId)
.Select(g=> new
{
GroupId = g.Key,
ValueA = g.Sum(x => x.ValueA),
ValueB = g.Sum(x => x.ValueB)
});
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