SQL查询特定日期的顶部和底部值

Question

SQL Server 2000

我的表:

CARDNO  CARDEVENTDATE   CARDEVENTTIME
121 20090610    025050
 121    20090611    040000
121 20090611    050000
121 20090611    020000
122 20090611    030001
122 20090611    030000
123 20090611    080000
123 20090611    100000
123 20090611    132449
123 20090611    025959
124 20090610    030000
124 20090612    030001
125 20090611    030002
125 20090612    040000

Cardno是独立的表Cardeventdate,cardeventtime是独立的表

从上表中我想获得特定cardeventdate和Cardno的最佳时间和最低时间

对于121,20090611,Top Time是040000,Bottom Time是020000 For 123,20090611,Top Time是080000,Bottom Time是025959 ...就像我需要的那样.

我使用了Min(时间)和Max(时间),但它显示了这样.

对于CardNo - 121 Cardeventdate - 20090611 Min Time - 020000 Max Time - 040000

我不想得到min和Max,我只需要特定Date和Cardno的top和Bottom(或)First和Last time值.

我用过这个查询

SELECT     RowNumber = IDENTITY (int, 1, 1), CARDNO, CARDEVENTDATE, CARDEVENTTIME INTO #Table1 FROM T_CARDEVENT SELECT     t1.CARDNO, t1.CARDEVENTDATE, t1.CARDEVENTTIME  FROM #Table t1 INNER JOIN (SELECT     RowNumber = MIN(RowNumber), CARDEVENTDATE, CARDNO  FROM  #Table1 t  WHERE      (cardeventdate > 20090601) GROUP BY cardno, cardeventdate  UNION ALL  SELECT     MAX(RowNumber), CARDEVENTDATE, CARDNO FROM #Table1 t WHERE     (cardeventdate > 20090601) GROUP BY cardno, cardeventdate) t2 ON t2.rownumber = t1.rownumber

输出:

ROWNUMBER   CARDNO  CARDEVENTDATE   CARDEVENTTIME
335 0121               20090611     040000
1099    0121               20090611     050000
1100    0121               20090611     025050
336 0121               20090612     020000
337 0122               20090611     030001
338 0122               20090612     030000
339 0123               20090611     080000
1101    0123               20090611     100000
1102    0123               20090611     132449
340 0123               20090612     025959
341 0124               20090611     030000
342 0124               20090612     030001
343 0125               20090611     030002
344 0125               20090612     040000

所以这里为所有列创建行号,从那里我必须采取特定日期的第一次和最后一次.

期待输出

CARDNO  CARDEVENTDATE   CARDEVENTTIME   Expecting
0121    20090611    040000  Top Value
0121    20090611    020000  No Need
0121    20090611    025050  Bottom Value

.........等等

需要查询帮助.

Answer 1

好吧,除非你有一些额外的字段来建立订单,否则这是不确定的.考虑到23-04-2009的三个值 - APPLE是第一个,ROSE是最后一个？如果所有三个条目的ID和DATE相同,则没有定义的顺序来过滤掉"GRAPHE"......

渣

更新:我稍微扩展了Lieven的想法,并在我的设置中使用了它:

DECLARE @TempTable TABLE (RowNumber INT IDENTITY(1,1), 
                          DayNumber INT, 
                          ID VARCHAR(3), DateField DATETIME, Value VARCHAR(32))

INSERT INTO @TempTable(DayNumber, id, datefield, value)
    SELECT DATEPART(DAYOFYEAR, DateField), ID, DateField, Value
    FROM @Table

SELECT * 
FROM @TempTable t
INNER JOIN 
   (SELECT RowNumber = MIN(RowNumber), DayNumber, ID
    FROM @TempTable t
    GROUP BY DayNumber, t.ID
    UNION ALL 
    SELECT MAX(RowNumber), DayNumber, ID
    FROM @TempTable t
    GROUP BY DayNumber, t.ID) t2 
  ON t2.RowNumber = t.RowNumber
GO

我基本上创建了一个带有附加信息的临时表 - 一个用于创建一些订单的人工"RowNumber",以及用于获取按日期分组的日期的"DayNumber"(没有时间).

似乎对我有用 - 它对你也有用吗？