我已经使用以下代码在类中实现了IEquatable接口.
public bool Equals(ClauseBE other)
{
if (this._id == other._id)
{
return true;
}
return false;
}
public override bool Equals(Object obj)
{
if (obj == null)
{
return base.Equals(obj);
}
if (!(obj is ClauseBE))
{
throw new InvalidCastException("The 'obj' argument is not a ClauseBE object.");
}
return Equals(obj as ClauseBE);
}
public override int GetHashCode()
{
return this._id.GetHashCode();
}
public static bool operator ==(ClauseBE a, ClauseBE b)
{
// cast to object so we call the overloaded Equals function which appropriately checks when b is null.
return a.Equals(b as object);
}
public static bool operator !=(ClauseBE a, ClauseBE b)
{
// cast to object so we call the overloaded Equals function which appropriately checks when b is null.
return !a.Equals(b as object);
}
Run Code Online (Sandbox Code Playgroud)
此代码适用于大多数情况.但是,以下检查会在等于运算符重载方法中引发异常,因为a为null,因此没有Equals方法.
if(this.Clause != null)
{
}
Run Code Online (Sandbox Code Playgroud)
解决此问题的标准方法是什么?
我已经去过这个,但看起来很麻烦.我希望有一种更优雅的方式来实现这一目标.
public static bool operator ==(ClauseBE a, ClauseBE b)
{
if (a as object == null && b as object == null)
{
return true;
}
if ((a as object == null && b as object != null)
|| (b as object == null && a as object != null))
{
return false;
}
// cast to object so we call the overloaded Equals function which appropriately checks when b is null.
return a.Equals(b as object);
}
public static bool operator !=(ClauseBE a, ClauseBE b)
{
if (a as object == null && b as object == null)
{
return false;
}
if((a as object == null && b as object != null)
|| (b as object == null && a as object != null))
{
return true;
}
// cast to object so we call the overloaded Equals function which appropriately checks when b is null.
return !a.Equals(b as object);
}
Run Code Online (Sandbox Code Playgroud)
谢谢大家.我从每个人那里得到了很多好的建议,我真的很感激.这是我最终确定的,它比我开始时更优雅.除运算符重载外,所有代码都相同.
public static bool operator ==(ClauseBE a, ClauseBE b)
{
if (ReferenceEquals(a, null) && ReferenceEquals(b, null))
{
return true;
}
if (ReferenceEquals(a, null) || ReferenceEquals(b, null))
{
return false;
}
return a.Equals(b);
}
public static bool operator !=(ClauseBE a, ClauseBE b)
{
return !(a == b);
}
Run Code Online (Sandbox Code Playgroud)
我总是发现使用null处理编写静态运算符更容易,并且使用Equals覆盖调用重载运算符,并将"this"作为参数之一.
//add this code to class ThreeDPoint as defined previously
//
public static bool operator ==(ThreeDPoint a, ThreeDPoint b)
{
// If both are null, or both are same instance, return true.
if (System.Object.ReferenceEquals(a, b))
{
return true;
}
// If one is null, but not both, return false.
if (((object)a == null) || ((object)b == null))
{
return false;
}
// Return true if the fields match:
return a.x == b.x && a.y == b.y && a.z == b.z;
}
public static bool operator !=(ThreeDPoint a, ThreeDPoint b)
{
return !(a == b);
}
Run Code Online (Sandbox Code Playgroud)