我有一些课.
class TreeNode
{
public TreeNode Left;
public TreeNode Right;
public int Value;
public TreeNode(int i)
{
Value = i;
}
public TreeNode AddLeft(int value)
{
Left = new TreeNode(value); ;
return Left;
}
public TreeNode AddRight(int value)
{
Right = new TreeNode(value);
return Right;
}
public static int GetSum(TreeNode root)
{
if(root.Left == null || root.Right == null) return root.Value;
return root.Value + GetSum(root.Left) + GetSum(root.Right);
}
}
class Program
{
static void Main(string[] args)
{
var root = new TreeNode(10);
var left = root.AddLeft(1);
left.AddLeft(1);
left.AddRight(1);
var right = root.AddRight(1);
right.AddLeft(1);
right.AddRight(1);
int Sum = TreeNode.GetSum(root);
Console.WriteLine("Sum is :{0}", Sum);
Console.ReadKey();
}
}
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如何简化树初始化,因为如果树很大,很容易混淆?
这样的事情:
var root = new TreeNode(10,
new TreeNode(1,
new TreeNode(1),
new TreeNode(1)),
new TreeNode(1,
new TreeNode(1),
new TreeNode(1)));
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看起来更清洁,你怎么看?您需要做的就是添加一个新的构造函数:
public TreeNode(int value, TreeNode left, TreeNode right)
{
Value = value;
Left = left;
Right = right;
}
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除了Daren Thomas的答案,如果你想让初始化更具可读性,你可以使用C#4.0 的命名参数功能
var root = new TreeNode(10,
left: new TreeNode(1,
left: new TreeNode(1),
right: new TreeNode(1)),
right: new TreeNode(1,
left: new TreeNode(1),
right: new TreeNode(1)));
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