achartengine在一个linegraph中的多行

Question

我试图根据此视频在图表中显示两行:http: //www.youtube.com/watch？v = 5DGldVzC-bU

我的代码:

public class LineGraph {
    public Intent getIntent(Context context){


        int[] x = {1,2,3,4,5,6,7,8,9,10}; 
        int[] y = {31,29,54,94,75,36,47,118,92,10};



        TimeSeries series = new TimeSeries("Line1");
        for (int i=0;i<x.length;i++){
            series.add(x[i],y[i]);
        }

        int[] x2 = {1,2,3,4,5,6,7,8,9,10}; 
        int[] y2 = {39,145,35,87,2,65,48,49,100,106};

        TimeSeries series2 = new TimeSeries("Line2");
        for (int i=0;i<x2.length;i++){
            series.add(x2[i],y2[i]);
        }



        XYMultipleSeriesDataset dataset = new XYMultipleSeriesDataset();
        dataset.addSeries(series);
        dataset.addSeries(series2);



        XYSeriesRenderer renderer = new XYSeriesRenderer();
        renderer.setColor(Color.CYAN);
        renderer.setPointStyle(PointStyle.SQUARE);
        renderer.setFillPoints(true);
        renderer.setLineWidth(3);
        renderer.setDisplayChartValues(true);

        XYSeriesRenderer renderer2 = new XYSeriesRenderer();
        renderer2.setColor(Color.BLACK);
        renderer2.setPointStyle(PointStyle.CIRCLE);
        renderer2.setFillPoints(true);
        renderer2.setLineWidth(3);
        renderer2.setDisplayChartValues(true);

        XYMultipleSeriesRenderer mrenderer = new XYMultipleSeriesRenderer();
        mrenderer.addSeriesRenderer(renderer);
        mrenderer.addSeriesRenderer(renderer2);

        mrenderer.setChartTitle("title");

        mrenderer.setBackgroundColor(Color.WHITE);

        mrenderer.setShowGrid(true);
        mrenderer.setApplyBackgroundColor(true);

        mrenderer.setXTitle("Days");
        mrenderer.setYTitle("datas");

        mrenderer.setGridColor(Color.GRAY);
    //  mrenderer.setZoomButtonsVisible(true);

        Intent intent = ChartFactory.getLineChartIntent(context, dataset, mrenderer, "Line graph title");
        return intent;

    }

实际上和视频一样.但我没有工作,而不是得到两个不同的线,我只得到一个.当第一行(x)的最后数据结束时,它转到第二行(x2)的第一个数据,因此第二行从第一行继续.提前致谢!

Answer 1

不应该如下:

series.add(x2[i],y2[i]);

实际上:

series2.add(x2[i],y2[i]);

注意'2'.