如何在Spring webapp中的JSP中获取正确的当前URL

use*_*935 37 url spring jsp web-applications request

我正在尝试在Spring webapp中的JSP中获取正确的当前URL.我正在尝试在JSP文件中使用以下片段:

${pageContext.request.requestURL}
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问题是返回的URL包含UrlBasedViewResolver定义的前缀和后缀.例如,正确的URL是:

HTTP://本地主机:8080 /页

但返回的是:

HTTP://本地主机:8080/WEB-INF/JSP/page.jsp

Pau*_*nis 48

最好的方法是使用这样的EL:

${requestScope['javax.servlet.forward.request_uri']}
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  • 这不起作用.它不会返回OP在问题评论中请求的绝对URL. (3认同)

izi*_*tti 5

也许你正在寻找类似的东西:

<%= new UrlPathHelper().getOriginatingRequestUri(request) %>
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这不是那么优雅,但解决了我的问题.


小智 5

jsp文件中:

request.getAttribute("javax.servlet.forward.request_uri")
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  • 在问题的注释中不返回OP请求的绝对URL. (3认同)

man*_*ish 0

您使用的是哪个 Spring 版本?我已经使用 Spring 3.1.1.RELEASE 对此进行了测试,使用以下简单的应用程序:

Folder structure
-----------------------------------------------------------------------------------

spring-web
    |
     --- src
          |
           --- main
                 |
                  --- webapp
                         |
                          --- page
                         |     |
                         |      --- home.jsp
                         |
                          --- WEB-INF
                               |
                                --- web.xml
                               |
                                --- applicationContext.xml

home.jsp
-----------------------------------------------------------------------------------

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">

<html dir="ltr" lang="en" xmlns="http://www.w3.org/1999/xhtml">
    <head>
        <title>Welcome to Spring Web!</title>
    </head>
    <body>
        Page URL: ${pageContext.request.requestURL}
    </body>
</html>

web.xml
-----------------------------------------------------------------------------------

<?xml version="1.0" encoding="UTF-8"?>

<web-app xmlns="http://java.sun.com/xml/ns/javaee" metadata-complete="true" version="2.5" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<display-name>org.example.web</display-name>

<servlet>
    <servlet-name>spring-mvc-dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/webContext.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>spring-mvc-dispatcher</servlet-name>
    <url-pattern>*.htm</url-pattern>
</servlet-mapping>
</web-app>

applicationContext.xml
-----------------------------------------------------------------------------------

<?xml version="1.0" encoding="UTF-8"?>

<beans xmlns="http://www.springframework.org/schema/beans" xmlns:context="http://www.springframework.org/schema/context" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:util="http://www.springframework.org/schema/util" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd     http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.1.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.1.xsd http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-3.1.xsd">

<context:annotation-config />
<context:component-scan base-package="org.example" />

<bean id="viewResolver"
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix" value="/page/" />
    <property name="suffix" value=".jsp" />
</bean>

<mvc:annotation-driven />
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访问http://localhost:8080/spring-web/page/home.jsp时,URL 正确显示为http://localhost:8080/spring-web/page/home.jsp