Django为什么来自urls.py的这一行有无效的语法?

Joh*_*ash 1 django django-templates django-urls django-views

     (r'^picks/(?P<choice>\w+)/$', 'app.views.picks', name='needed_picks'),
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这行由于某种原因给我一个无效的语法错误..想法?

Jam*_*esO 8

您的网址模式令人困惑,必须使用名称

url(r'^picks/(?P<choice>\w+)/$', 'app.views.picks', name='needed_picks'),
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