"功能不存在",但我认为确实如此

Question

我疯了还是只是愚蠢的？

dev=# \df abuse_resolve 
List of functions
-[ RECORD 1 ]-------+------------------------------------------------------------------------------------------------------------------------------------
Schema              | public
Name                | abuse_resolve
Result data type    | record
Argument data types | INOUT __abuse_id bigint, OUT __msg character varying
Type                | normal

dev=# select abuse_resolve('30'::bigint); 
ERROR:  function abuse_resolve(bigint) does not exist
LINE 1: select abuse_resolve('30'::bigint);
               ^
HINT:  No function matches the given name and argument types. You might need to add explicit type casts.

这是CREATE FUNCTION,我省略了代码的内容,但这应该是无关紧要的:

CREATE OR REPLACE FUNCTION abuse_resolve(INOUT __abuse_id bigint, OUT __msg character varying) RETURNS record AS $_$
DECLARE
    __abuse_status    VARCHAR;
BEGIN
 ...snip...
    UPDATE abuse SET abuse_status    = __abuse_status,
                       edate    = now(),
                       closed_on = now()
                 WHERE abuse_id        = __abuse_id;
    __msg = 'SUCCESS';
END;
$_$ LANGUAGE plpgsql SECURITY DEFINER;

只是为了咯咯笑:

GRANT ALL ON FUNCTION abuse_resolve(INOUT __abuse_id, OUT __msg character varying) TO PUBLIC;
GRANT ALL ON FUNCTION abuse_resolve(INOUT __abuse_id, OUT __msg character varying) TO myuser;

该功能似乎存在.我能错过什么？

这个问题得到解决,答案是:我很笨.我最初没有正确定义参数,但我的代码使用了正确的参数.有一个额外的bigint没有业务在那里.

Answer 1

嗯，有些奇怪。我做了：

steve@steve@[local] =# create function abuse_resolve(inout __abuse_id bigint,
                               out __msg text) returns record language plpgsql as
                               $$ begin __msg = 'ok'; end; $$;
CREATE FUNCTION
steve@steve@[local] =# \df abuse_resolve
List of functions
-[ RECORD 1 ]-------+----------------------------------------
Schema              | so9679418
Name                | abuse_resolve
Result data type    | record
Argument data types | INOUT __abuse_id bigint, OUT __msg text
Type                | normal

steve@steve@[local] =# select abuse_resolve('30'::bigint);
-[ RECORD 1 ]-+--------
abuse_resolve | (30,ok)

您对该数据库还有其他问题吗？您可以使用转储/恢复来复制它并在新副本上尝试此操作吗？使用“公共”模式显式限定函数名称是否有帮助？您使用的是哪个版本的 PostgreSQL？

更新：sql 函数 它对我来说也很好用：

create function abuse_resolve(inout __abuse_id bigint, out __msg text)
  language sql as $$ select $1, 'ok'::text $$;