如何从左上角到右边填充QGridLayout？

Question

我想填充QGridLayout用QWidgets.在QWidgets需要出现在左上至右上的方式,并继续向下填补了下来每一行充满后QWidgets.类似且熟悉的GUI的一个例子是Apple如何在iPhone或iPad的主屏幕上对其应用程序进行分类.应用程序从左上角到右上角,并在每行填充后继续向下移动.

现在,每当我添加元素时,它们都会占据整个屏幕和/或不会彼此相邻添加.

这是我正在做的示例代码

m_gridLayout = new QGridLayout(this);
this->setLayout(m_gridLayout);
m_gridLayout->addWidget(widgetToBeAdded, m_currentRow, m_currentColumn, Qt::AlignLeft);

我按预期继续更新m_currentColumn和m_currentRow.在一定数量的列之后,我告诉它改为下一行,没有任何反应.我已通过调试确认它实际上正在吐出正确的行和列.)

最后,我需要抛出一个,QScrollArea以便可以向下滚动网格.

每个的大小都是QWidget一样的.如果我能够在正确分类网格方面获得任何帮助,我们将不胜感激.

编辑:使用下面的答案,我设法让我的项目按正确的顺序排序.但是,在垂直方向上的所有元素之间存在大量空间.正如我想的那样,改变verticalSpacing属性并不能避免这种情况.有谁知道怎么办？

Answer 1

编写自己的网格布局,如下所示:

头

#ifndef MY_GRID_LAYOUT_H
#define MY_GRID_LAYOUT_H

#include <QGridLayout>

class my_grid_layout : public QGridLayout
{
public:
    my_grid_layout(QWidget *parent, int max_column_count );
    ~my_grid_layout();

    void add_widget( QWidget* p_widget );

private:
    int m_max_column_count;
};

#endif // MY_GRID_LAYOUT_H

资源

#include "my_grid_layout.h"

my_grid_layout::my_grid_layout(QWidget *parent, int max_column_count)
    : QGridLayout(parent)
{
    m_max_column_count = max_column_count;
}

my_grid_layout::~my_grid_layout()
{

}

void my_grid_layout::add_widget( QWidget* p_widget )
{
    int current_row = 0;
    int current_column = 0;

    while( itemAtPosition(current_row, current_column) != 0 )
    {
        if( current_column == (m_max_column_count-1) )
        {
            current_column = 0;
            ++current_row;
        }
        else
        {
            ++current_column;
        }
    }

    QGridLayout::addWidget( p_widget, current_row, current_column );
}

在主窗口中测试

#include "test_1.h"

Test_1::Test_1(QWidget *parent, Qt::WFlags flags)
    : QMainWindow(parent, flags)
{
    m_grid_layout = new my_grid_layout(this,4);

    m_grid_layout->add_widget( new QPushButton( "Widget 0", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 1", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 2", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 3", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 4", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 5", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 6", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 7", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 8", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 9", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 10", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 11", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 12", this ) );
    m_grid_layout->add_widget( new QPushButton( "Widget 13", this ) );



    QWidget* central_widget = new QWidget(this);
    central_widget->setLayout(m_grid_layout);

    setCentralWidget(central_widget);
}

Test_1::~Test_1()
{

}

结果

虽然在某个位置已经有一个项目,但切换到网格布局中的下一个位置,在我的示例中最大列数为4.我只是切换到下一栏,直到我到达第4列.然后我将列重置为0并切换到下一行.只要已有物品,我就这样做.只要那个地方没有物品,我就把我的小部件放在那里.

这只是一个简单的例子,但也许这对你来说已经足够了.

你应该通过错误处理来增强它,注意无限循环等......