当我在2上调用+时,我得到了一个Int,但是当使用显式方法调用完成时,我得到了Double.
scala> 2+2
res1: Int = 4
scala> 2.+(2)
res2: Double = 4.0
Run Code Online (Sandbox Code Playgroud)
看起来.+()是在隐式转换为Int到Double的情况下调用的.
scala> 2.+
<console>:16: error: ambiguous reference to overloaded definition,
both method + in class Double of type (x: Char)Double
and method + in class Double of type (x: Short)Double
match expected type ?
2.+
^
Run Code Online (Sandbox Code Playgroud)
为什么会这样 ?
Deb*_*ski 20
在Scala 2.9和之前,2.
被解释为2.0
模糊点表示浮点文字.您可以使用语法显式调用该方法(2).+(2)
.
然而,不明确的浮点语法将在2.10中弃用:
scala> 2.+(2)
<console>:1: warning: This lexical syntax is deprecated. From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
2.+(2)
^
<console>:2: warning: This lexical syntax is deprecated. From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
2.+(2)
^
<console>:8: warning: This lexical syntax is deprecated. From scala 2.11, a dot will only be considered part of a number if it is immediately followed by a digit.
2.+(2)
^
res1: Double = 4.0
Run Code Online (Sandbox Code Playgroud)
om-*_*nom 16
原因不在于显式方法调用 - 通过编写2.+
左侧指定Double然后在其上调用加法运算符:
scala> 2.
res0: Double = 2.0
Run Code Online (Sandbox Code Playgroud)
归档时间: |
|
查看次数: |
857 次 |
最近记录: |