将QLineEdit的"enter"事件链接到插槽？

Question

我有以下代码:

def init_widgets(self):
        mainLayout = QtGui.QGridLayout()

        self.label1 = QtGui.QLabel("Enter a song name: ")
        self.search_lineEdit = QtGui.QLineEdit()
        self.search_button = QtGui.QPushButton("&Search") # QCommandLinkButton
        self.search_button.clicked.connect(self.search_slot)
        self.table = self.createTable()
        self.label2 = QtGui.QLabel("iQuality v1.00 by Itay Brandes")

        mainLayout.addWidget(self.label1, 0, 0)
        mainLayout.addWidget(self.search_lineEdit, 0, 1)
        mainLayout.addWidget(self.search_button, 0, 2)
        mainLayout.addWidget(self.table, 1, 0, 1, 0)
        mainLayout.addWidget(self.label2, 2, 0)

        self.setLayout(mainLayout)

self.search_slot如果用户按下输入按钮,我该如何运行self.search_lineEdit？

Answer 1

QLineEdit有一个returnPressed信号.您可以将该信号连接search_lineEdit到自定义插槽.

不熟悉PyQt语法,但应该是这样的:

 self.search_lineEdit.returnPressed.connect(self.search_slot)