Xcode iOS:将int转换为NSString

Question

我试图从UIPicker中获取avalue,其中包含圆形数字,从中抽取的整数和NSMutableArray.我正在尝试将拉出的值转换为实际的int.

我在.m中试过这个:

int pickednumber;


......

-(void) pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component{


NSString *numbers = [arrayNumbers objectAtIndex:[pickerView selectedRowInComponent:0]];

pickednumber = [NSString stringWithFormat:@"%d", numbers];

NSLog(@"Picked number %@ ", numbers); 

}

我在picknumber = line中得到错误:指向整数转换的不兼容指针从'id'分配给'int'.我究竟做错了什么？

消息由Sounddesigner于3月8日下午3:05编辑

Answer 1

NSString有一个方便的方法来获取文本的整数值

做这个

pickednumber = [numbers intValue];

NSLog(@"Picked number %d ", numbers);  // not %@ ..%@ is for objects .. not int

Answer 2

NSString *intString = [NSString stringWithFormat:@"%d", myInt];

http://forums.macrumors.com/showthread.php?t=448594